Cambridge IGCSE · Topic 11.2
IGCSE Chemistry 0620 / Topic 11 / IGCSE

Stem plus ending.

Every organic name is built from two parts: a stem that counts the carbon atoms and an ending that names the family. Learn four stems and five endings and you can name, and draw, any compound on the IGCSE syllabus.

The key idea

The stem counts the carbon atoms in the chain: meth- 1, eth- 2, prop- 3, but- 4. The ending names the homologous series: -ane for alkanes, -ene for alkenes, -ol for alcohols and -oic acid for carboxylic acids. A number shows where the functional group sits when it could be in more than one place, as in propan-1-ol or but-2-ene. (Extended) An ester is named alcohol part first (ending -yl) then acid part (ending -oate): ethanol + ethanoic acid gives ethyl ethanoate. (Extended) Structural isomers have the same molecular formula but different structural formulae, such as butane and methylpropane (both C4H10).

stem: carbon atoms ending: homologous series 1 Cmeth- 2 Ceth- 3 Cprop- 4 Cbut- -anealkanes, C−C only -enealkenes, C=C -olalcohols, −OH -oic acidcarboxylic acids, −COOH -yl -oateesters, −COO− prop + ene = propene, CH₃CH=CH₂ but + anoic acid = butanoic acid, CH₃CH₂CH₂COOH
Fig. 1: the stem counts carbons, the ending names the homologous series
Section 01

Name it, then draw it.

Pick a stem and an ending in the simulator and check that your displayed formula matches the name. Count the carbons first, then place the functional group.

CarbonsAlkaneAlkeneAlcoholCarboxylic acid
1methane CH4(none)methanol CH3OHmethanoic acid HCOOH
2ethane C2H6ethene CH2=CH2ethanol CH3CH2OHethanoic acid CH3COOH
3propane C3H8propene CH3CH=CH2propan-1-ol CH3CH2CH2OHpropanoic acid CH3CH2COOH
4butane C4H10but-1-ene CH2=CHCH2CH3butan-1-ol CH3(CH2)3OHbutanoic acid CH3CH2CH2COOH

In a carboxylic acid the carbon of the −COOH group counts in the stem: ethanoic acid has two carbons, CH3 and COOH. There is no "methene", because a C=C bond needs at least two carbons.

Extended. Esters: name the alcohol part first, then the acid part. Methanol + ethanoic acid → methyl ethanoate, CH3COOCH3; ethanol + propanoic acid → ethyl propanoate, CH3CH2COOCH2CH3.

Stage 1 · Learn

Check what the sim just showed you

Four quick checks. Each correct answer earns XP and records this skill on your profile.

Quick check+10 XP

What is the name of CH3CH2CH3?

Quick check+10 XP

Which compound is butanoic acid?

Quick check+10 XP

What is the name of CH3OH?

Quick check+10 XP

Which name is correct for CH2=CH2?

Section 02

Structural isomers.

Extended. Rearrange the atoms of C4H10 in the simulator. Every arrangement has the same molecular formula, but the atoms are joined differently.

Examiner trap

A chain drawn with a bend is the same molecule, not an isomer: follow the bonds, not the shape on the page. Name the longest unbroken carbon chain, so a "bent butane" is still butane. In esters the alcohol gives the first word (ethyl) and the acid gives the second (ethanoate), the reverse of the order in the word equation.

Stage 2 · Exam

Exam-style questions

Unlocks once the four checks above are done. Worth more XP, written to IGCSE Paper 2 and Paper 4 standard.

Finish the four checks above to unlock the exam questions
Exam style+20 XP

(Extended) Which ester is made from ethanol and ethanoic acid?

Exam style+20 XP

(Extended) Which pair are structural isomers?

Exam style+20 XP

(Extended) Which compound is an isomer of butane, C4H10?

Exam style+20 XP

Which is the structural formula of propan-2-ol?

Skill unlocked

Naming organic compounds, mastered.

This skill is now recorded on your profile. Keep the chain going.

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Go deeper · practice
Six original Cambridge-style questions
Naming and drawing alkanes, alkenes, alcohols and carboxylic acids up to four carbons, esters and structural isomers.