IGCSE · Practice questions · The mole and gas volumes

Count it by mass.

Six original Cambridge-style questions on the mole: mass, number of particles and the molar gas volume of 24 dm3 at r.t.p. Extended content.

Original questions All questions on this page are original work, written in the Cambridge IGCSE style. They are not from past papers. They test the same concepts and skills the syllabus rewards.
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Go through the mole every time.

01
Recall
[1 marks]

State the number of particles in one mole of a substance.

  • 6.02 × 1023 particles (the Avogadro constant). ✓
02
Calculation
[3 marks]

For 22 g of carbon dioxide, CO2, calculate (a) the number of moles, (b) the number of molecules and (c) its volume at r.t.p. (Ar: C 12, O 16)

  • (a) Mr = 44, so moles = 22 ÷ 44 = 0.5 mol. ✓
  • (b) 0.5 × 6.02 × 1023 = 3.01 × 1023 molecules. ✓
  • (c) 0.5 × 24 = 12 dm3. ✓
03
Calculation
[2 marks]

Calculate the volume, in cm3, occupied by 0.16 g of oxygen gas, O2, at r.t.p. (Ar: O 16)

  • Mr of O2 = 32, so moles = 0.16 ÷ 32 = 0.005 mol. ✓
  • Volume = 0.005 × 24 000 = 120 cm3. ✓
04
Calculation
[2 marks]

Calculate the mass of 600 cm3 of carbon dioxide at r.t.p. (Ar: C 12, O 16)

  • Moles = 600 ÷ 24 000 = 0.025 mol. ✓
  • Mass = 0.025 × 44 = 1.1 g. ✓
05
Analysis
[3 marks]

A student has 4 g of hydrogen gas, H2, and 32 g of oxygen gas, O2. Which sample contains more molecules, and which has the larger volume at r.t.p.? Show your working. (Ar: H 1, O 16)

  • Hydrogen: 4 ÷ 2 = 2 mol. Oxygen: 32 ÷ 32 = 1 mol. ✓
  • Hydrogen has twice as many molecules (1.20 × 1024 against 6.02 × 1023). ✓
  • Hydrogen also has the larger volume: 2 × 24 = 48 dm3 against 24 dm3. ✓
06
Calculation
[2 marks]

Calculate the mass of 3.01 × 1022 atoms of zinc. (Ar: Zn 65)

  • Moles = 3.01 × 1022 ÷ 6.02 × 1023 = 0.05 mol. ✓
  • Mass = 0.05 × 65 = 3.25 g. ✓

Mark this once you have attempted all six and checked your working. It records a Practiced badge on the topic and adds a one-time bonus. Revealing the solutions alone does not count.