Hang a load on the spring and watch it stretch. While the load stays below the limit of proportionality, the extension is proportional to the load: this is Hooke's law, force equals the spring constant times extension. Past that limit the line curves and the spring no longer returns the same way. Spring A is stiffer than spring B, so for the same load it stretches less.
MissionStretch spring A to exactly 20 cm. Find the load that does it.Round 1Streak 0Best 0
For the same load, which stretches more?
load F5.0 N
extension x10.0 cm
spring constant k = F ÷ x50 N/m
regionobeys Hooke's law
F = k x, so x = F ÷ k while below the limit of proportionality.