A Level · Topic 18.2
A-Level Biology 9700 / Topic 18 / A2

Count a sample, estimate the whole.

Nobody can count every plant in a meadow or every beetle in a wood. This lesson defines ecosystem and niche, sets out the three levels of biodiversity, and shows how random quadrats, Simpson's index and mark-release-recapture turn a fair sample into numbers you can compare.

The key idea

An ecosystem is a community of organisms and its physical environment, interacting; a niche is the role of a species in its ecosystem, including what it feeds on, where it lives and how it interacts with other organisms and the environment. Biodiversity can be assessed at three levels: the number and range of ecosystems and habitats, the number of species and their relative abundance, and the genetic variation within each species. Samples must be random to avoid bias. Frame quadrats placed at random coordinates give density, frequency or percentage cover of plants and slow-moving animals, and Simpson's index of diversity, D = 1 − Σ(n/N)2, combines richness and evenness on a scale of 0 to 1. Mobile animals are estimated by mark-release-recapture with the Lincoln index, N = (n1 × n2) ÷ m2.

Site A: even Site B: one species dominates 2020202020 805555 5 species, N = 100 5 species, N = 100 Σ(n/N)² = 0.20 D = 0.80 Σ(n/N)² = 0.65 D = 0.35 D = 1 − Σ(n/N)²: same species richness, different evenness
Fig. 1: two sites with the same five species and the same total; the even site has the higher Simpson's index
Section 01

Ecosystems, niches and three levels of biodiversity.

Biodiversity is more than a list of species. Before sampling, be clear what you are measuring.

Level of biodiversityWhat is assessed
ecosystems and habitatsthe number and range of different ecosystems and habitats in an area (for example forest, grassland, wetland, coral reef)
speciesspecies richness (the number of species) and the relative abundance of each, that is, how evenly individuals are spread among the species
geneticthe genetic variation within each species: the number of different alleles of each gene in the population
Section 02

Random quadrats and Simpson's index.

Choose the wild meadow and press Place 10 random quadrats. Read the counts of the five species and Simpson's D. Then switch to the lawn, where clover dominates, and sample again.

Examiner trap

Square each n/N before adding, then subtract the total from 1. Adding the n/N values first always gives 1, and forgetting the final subtraction gives a number that falls as diversity rises.

Section 03

Mark, release, recapture.

Press 1. Catch and mark, 2. Release and wait, then 3. Second catch. Compare the Lincoln index estimate with the true population shown in brackets, and repeat to see how much the estimate varies.

Examiner trap

Put the recaptured marked number m2 on the bottom. If marked animals are more likely to be caught a second time (trap-happy), m2 is too large and the population is underestimated.

Stage 1 · Learn

Check what the sim just showed you

Four quick checks. Each correct answer earns XP and records this skill on your profile.

Quick check+10 XP

In the quadrat tab, why is the lawn's Simpson's index lower than the wild meadow's?

Quick check+10 XP

How does the simulator choose where to put each quadrat?

Quick check+10 XP

In the mark-release-recapture tab, why must you press Release and wait before the second catch?

Quick check+10 XP

A run of the simulator gives n1 = 30, n2 = 40 and m2 = 6. What is the Lincoln index estimate?

Stage 2 · Exam

Exam-style questions

Unlocks once the four checks above are done. Worth more XP, written to A Level Paper 4 standard.

Finish the four checks above to unlock the exam questions
Exam style+20 XP

Three species are counted in random quadrats: 10, 6 and 4 individuals. What is Simpson's index of diversity, D?

Exam style+20 XP

Which statement best describes the niche of a species?

Exam style+20 XP

Which method is most suitable for estimating the population of woodlice in a garden?

Exam style+20 XP

Two forests have the same number of tree species. Forest P has D = 0.85 and forest Q has D = 0.40. Which conclusion is valid?

Skill unlocked

Sampling and measuring biodiversity, mastered.

This skill is now recorded on your profile. Keep the chain going.

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Go deeper · practice
Six original Cambridge-style questions
Ecosystem and niche, the three levels of biodiversity, random sampling, frame quadrats, Simpson's index of diversity and mark-release-recapture with the Lincoln index.