Home / A-Level Biology 9700 / Topic 6 / Revision notes
Download PDFQuestion bank →Topic 6 lessons

Nucleic acids and protein synthesis

A-Level Biology 9700 · Topic 6 revision notes

Everything from the 4 lessons of this topic on a few pages: the key idea of each lesson, the diagram to remember, the points to learn and the traps examiners set. Read it, cover it, test yourself.

  1. The structure of nucleic acids
  2. Semi-conservative replication of DNA
  3. Transcription and translation
  4. Gene mutations

1The structure of nucleic acids

Syllabus 6.1

A nucleotide is a phosphate group, a pentose sugar (deoxyribose in DNA, ribose in RNA) and a nitrogen-containing base. Adenine and guanine are purines with a double ring; cytosine, thymine and uracil are pyrimidines with a single ring. ATP is a phosphorylated nucleotide: adenine, ribose and three phosphates. Nucleotides are joined into a polynucleotide by phosphodiester bonds (condensation reactions) between the phosphate of one and the sugar of the next. DNA is a double helix of two antiparallel strands, one running 5′ to 3′ and the other 3′ to 5′, held together by hydrogen bonds between complementary bases: A with T (two hydrogen bonds) and C with G (three). mRNA is a single, short, unpaired polynucleotide with ribose and uracil in place of deoxyribose and thymine.

5′ end 3′ end 3′ end 5′ end A T G C C G A-T: 2 hydrogen bonds C-G: 3 hydrogen bonds phosphate deoxyribose sugar- phosphate backbone antiparallel strands; a purine always pairs with a pyrimidine
Fig. 1: a short length of DNA, untwisted; the two sugar-phosphate backbones run in opposite directions and the bases pair inside

Sugar, base, bond.

  • Purines (A, G) double ring; pyrimidines (C, T, U) single ring.
  • Phosphodiester bonds within a strand; hydrogen bonds between strands.
  • A-T: 2 hydrogen bonds; C-G: 3.
  • Antiparallel: 5′ to 3′ alongside 3′ to 5′.

Watch out!

Do not say thymine is a purine because it pairs with adenine. Pairing tells you nothing about the class: every pair is one of each. Learn the ring count instead (memory aid: pure As Gold): adenine and guanine are the double-ringed purines; C, T and U are single-ringed pyrimidines.

Antiparallel does not just mean the strands are side by side. It means they run in opposite directions: where one strand has its 5′ end, the other has its 3′ end.

2Semi-conservative replication of DNA

Syllabus 6.1

DNA is copied during the S phase of the cell cycle. The hydrogen bonds between bases break and the double helix unwinds, so each strand is exposed as a template. Free DNA nucleotides pair with the exposed bases by complementary base pairing (A with T, C with G). DNA polymerase joins the new nucleotides by forming phosphodiester bonds, but it can add nucleotides only to the 3′ end of a growing strand, so new DNA is always built in the 5′ to 3′ direction. On one template the new strand grows towards the replication fork continuously (the leading strand); on the other it must grow away from the fork, in short fragments (the lagging strand), which DNA ligase joins with phosphodiester bonds. Each daughter molecule has one original and one new strand: replication is semi-conservative.

parent DNA 3′ 5′ 5′ leading strand: continuous, towards the fork lagging strand: fragments, away from the fork red dots: gaps sealed by DNA ligase fork moves → blue = old template strands; amber = new strands; arrowheads = 3′ ends
Fig. 1: a replication fork; new DNA grows only 5′ to 3′, so one new strand is continuous and the other is made in fragments

Template, polymerase, ligase.

  • Semi-conservative: each new molecule = one old strand + one new.
  • DNA polymerase builds new strands 5′ to 3′ only.
  • Leading: continuous. Lagging: fragments joined by DNA ligase.
  • Both enzymes make phosphodiester bonds; hydrogen bonds form by pairing.

Watch out!

Do not say DNA polymerase builds the lagging strand 3′ to 5′. It never does: both new strands are made 5′ to 3′. The lagging strand is in fragments precisely because its 5′ to 3′ direction points away from the fork.

The intermediate band never disappears in later generations: the two original heavy strands are kept, so there are always exactly two hybrid molecules. Only their proportion halves each generation.

3Transcription and translation

Syllabus 6.2

A polypeptide is coded for by a gene, a sequence of nucleotides forming part of a DNA molecule. The genetic code is a triplet code: each group of three bases codes for one amino acid, or acts as a start or stop signal, and it is universal (the same in almost all organisms). In transcription, in the nucleus, RNA polymerase separates the strands of the gene and builds mRNA complementary to the template (transcribed) strand; the other is the non-transcribed strand. In eukaryotes the primary transcript is modified: introns (non-coding) are removed and exons (coding) are joined. In translation, at a ribosome in the cytoplasm, each tRNA carries a specific amino acid and has an anticodon complementary to an mRNA codon. Starting at AUG, amino acids are joined by peptide bonds until a stop codon is reached.

coding strand template strand mRNA (codons) tRNA anticodons amino acids 5′ ATG GCC TTC … 3′ 3′ TAC CGG AAG … 5′ transcription: RNA polymerase AUG GCC UUC UAC CGG AAG translation: ribosome MetAlaPhe mRNA = coding strand with U for T; one codon, one amino acid
Fig. 1: the first three codons of the gene in the lab, from DNA to mRNA to tRNA to amino acids

Template, codon, anticodon.

  • mRNA = complement of the template strand = coding strand with U for T.
  • Anticodon on tRNA is complementary to the codon on mRNA.
  • Start AUG (Met); stop codons have no tRNA.
  • Introns removed, exons joined, before mRNA leaves the nucleus.

Watch out!

mRNA is complementary to the template strand, not to the coding strand. So the mRNA reads the same as the coding (non-transcribed) strand, with U instead of T. If you are given the template strand, pair every base and swap T for U.

Remember which is which: exons are expressed (they stay in the mRNA); introns are in the way (they are removed). It is the RNA that is edited, not the DNA: the introns stay in the gene.

4Gene mutations

Syllabus 6.2

A gene mutation is a change in the sequence of base pairs in a DNA molecule that may result in an altered polypeptide. In a substitution one base pair is replaced by another, so only one codon changes: because the code is degenerate it may still code for the same amino acid (no effect), it may code for a different amino acid (as in sickle cell anaemia, where glutamic acid becomes valine in β-globin), or it may become a stop codon (a shortened polypeptide). A deletion or insertion of one nucleotide causes a frameshift: every codon after the mutation is read differently, so many amino acids change and a stop codon often appears early. The polypeptide usually folds wrongly and cannot function.

original substitution deletion AUG GUG CAC CUG ACU CCU AUG GUG CAC CUG ACU CAU AUG GUG CAC CGA CUC CUG Met-Val-His-Leu-Thr-Pro Met-Val-His-Leu-Thr-His Met-Val-His-Arg-Leu-Leu one codon changed: at most one amino acid frameshift: every codon after the deleted U changes mRNA read in triplets from AUG red = changed; an insertion also shifts the reading frame
Fig. 1: the start of the β-globin mRNA after a substitution and after a deletion; only the deletion shifts the reading frame

Codon, frame, function.

  • Gene mutation = change in DNA base sequence; may alter the polypeptide.
  • Substitution changes one codon: same, different or stop.
  • Deletion / insertion of one base: frameshift.
  • Explain effects via primary structure, folding and function.

Watch out!

Do not write that a mutation is a change in an amino acid or in a protein. A gene mutation is a change in the DNA base sequence; a changed polypeptide is a possible consequence.

Back to A-Level Biology 9700 contents · (c) 2026 TheLucidSTEM · thelucidstem.com