Six original Cambridge-style questions on polymer deductions.
A section of a polymer is –NH(CH2)4NHCO(CH2)3CO–NH(CH2)4NHCO(CH2)3CO–. (a) Identify the type of polymer. (b) Give the structures of the two monomers.
Draw the repeat unit of the polymer formed from 3-hydroxypropanoic acid, HOCH2CH2COOH, and name the type of polymer.
For each monomer, state whether it forms an addition or a condensation polymer: (a) CH2=CHC6H5, (b) H2NCH(CH3)COOH, (c) CH2=CHCOOH.
Explain why nylon-6,6 has a higher melting point than poly(ethene) of similar chain length.
A polymer section is –CH2CCl2CH2CCl2–. Give the monomer and explain how you know the type of polymerisation.
Suggest why poly(lactic acid) chains cannot hydrogen bond to each other, whereas protein chains can.
Mark this once you have attempted all six and checked your working. It records a Practiced badge on the topic and adds a one-time bonus. Revealing the solutions alone does not count.