AS Level · Topic 11.4
A-Level Chemistry 9701 / Topic 11 / AS

Oxidised and reduced at once.

In sodium hydroxide, some chlorine atoms gain electrons while others lose them. That disproportionation makes household bleach, and a similar reaction with water is why chlorine keeps drinking water safe.

The key idea

Disproportionation is a redox reaction in which the same element is simultaneously oxidised and reduced. Chlorine (oxidation number 0) disproportionates in sodium hydroxide: in cold, dilute NaOH it forms NaCl (−1) and NaClO (+1), the mixture used as bleach; in hot, concentrated NaOH it forms NaCl (−1) and NaClO3 (+5). With water, Cl2 + H2O ⇌ HCl + HClO, and the chloric(I) acid kills bacteria, which is why chlorine is used to treat drinking water.

+5+10−1 Cl₂ClO⁻Cl⁻ClO₃⁻ cold, dilute NaOH Cl₂ + 2NaOH → NaCl + NaClO + H₂O 0 → −1 and 0 → +1 hot, concentrated NaOH 3Cl₂ + 6NaOH → 5NaCl + NaClO₃ + 3H₂O 0 → −1 and 0 → +5 disproportionation: chlorine is oxidised and reduced at the same time
Fig. 1: oxidation numbers of chlorine in its reactions with sodium hydroxide
Section 01

In alkali and in water.

Bubble chlorine into cold dilute and hot concentrated sodium hydroxide in the simulator, then into water, and track the oxidation number of chlorine in each product.

ConditionsEquationOxidation numbers of Cl
cold, dilute NaOHCl2 + 2NaOH → NaCl + NaClO + H2O0 → −1 and +1
hot, concentrated NaOH3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O0 → −1 and +5
waterCl2 + H2O ⇌ HCl + HClO0 → −1 and +1
Stage 1 · Learn

Check what the sim just showed you

Four quick checks. Each correct answer earns XP and records this skill on your profile.

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What is disproportionation?

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What are the chlorine-containing products when chlorine reacts with cold, dilute sodium hydroxide?

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What is the oxidation number of chlorine in NaClO3?

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Why is chlorine added to drinking water?

Section 02

Treating water.

Adding a small amount of chlorine to drinking water saves millions of lives, but it is not without risk.

Examiner trap

In disproportionation the same element is both oxidised and reduced, so chlorine appears in two products with different oxidation numbers. Do not mix up the two NaOH conditions: cold dilute gives chlorate(I), NaClO; hot concentrated gives chlorate(V), NaClO3.

Stage 2 · Exam

Exam-style questions

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In 3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O, which statement is correct?

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What is the oxidation number of chlorine in chloric(I) acid, HClO?

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Which is a risk of chlorinating drinking water?

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0.710 g of Cl2 (Mr 71.0) reacts with excess cold dilute NaOH. What mass of NaClO (Mr 74.5) forms?

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Six original Cambridge-style questions
Disproportionation of chlorine in cold and hot sodium hydroxide, its reaction with water, and the benefits and risks of water chlorination.