A Level · Topic 29.3
A-Level Chemistry 9701 / Topic 29 / A2

Six electrons shared by six carbons.

Kekulé drew benzene with three alternating double bonds. The bond lengths, the enthalpy of hydrogenation and benzene's reluctance to add bromine all say otherwise: the pi electrons are spread round the whole ring.

The key idea

Each carbon in benzene is sp2 hybridised: it forms three sigma bonds (two to C, one to H) in a plane at 120°, so the ring is planar. The remaining p orbital on each carbon overlaps sideways with both neighbours, forming a delocalised pi system of six electrons in rings above and below the plane. The evidence against the Kekulé structure is threefold: all six C–C bonds are 0.139 nm, between C–C (0.154 nm) and C=C (0.134 nm); the enthalpy of hydrogenation is −208 kJ mol−1, not the −360 kJ mol−1 predicted from three C=C bonds, so benzene is about 152 kJ mol−1 more stable; and benzene resists addition, preferring substitution that keeps the delocalised ring.

Kekulé modeldelocalised model alternating C=C and C–C 0.134 nm and 0.154 nm six equal C–C bonds all 0.139 nm ΔH hydrogenation: predicted 3 × (−120) = −360, actual −208 kJ mol⁻¹ delocalisation makes benzene 152 kJ mol⁻¹ more stable
Fig. 1: the Kekulé model against the delocalised model of benzene
Section 01

Orbitals in the ring.

Toggle between the Kekulé structure and the delocalised ring in the simulator, and compare the sideways overlap in ethene with the continuous overlap round a benzene ring.

FeatureBenzeneReason
hybridisation of each Csp2three bonding regions around each carbon
bond angle120°three regions repel to a trigonal planar arrangement
shapeplanar hexagonall twelve atoms lie in one plane
sigma bonds12six C–C plus six C–H
pi electrons6one from the p orbital of each carbon, delocalised above and below the ring
Section 02

The evidence against Kekulé.

Three independent observations all point the same way. Learn the numbers.

EvidenceKekulé predictsObserved
C–C bond lengthsthree of 0.154 nm and three of 0.134 nmall six 0.139 nm
enthalpy of hydrogenation3 × (−120) = −360 kJ mol−1−208 kJ mol−1
reaction with bromine waterrapid decolourisation (addition)no reaction; substitution needs a FeBr3 catalyst
Examiner trap

The circle does not mean benzene has no double bond character: every C–C bond has some. Stabilisation is 152 kJ mol−1, the gap between −360 and −208, not 208. The pi electrons are above and below the plane of the ring, not in it; the sigma framework lies in the plane.

Stage 1 · Learn

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What is the hybridisation of each carbon atom in benzene?

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What is the C–C–C bond angle in benzene?

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Where are the delocalised electrons in benzene?

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How long is each carbon-carbon bond in benzene?

Stage 2 · Exam

Exam-style questions

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The enthalpy change of hydrogenation of cyclohexene is −120 kJ mol−1 and of benzene is −208 kJ mol−1. What is the stabilisation energy of benzene?

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Which observation is NOT evidence that benzene has a delocalised structure?

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Why does benzene undergo substitution rather than addition with bromine?

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How many sigma bonds and how many delocalised pi electrons are there in one benzene molecule?

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Structure of benzene, mastered.

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Go deeper · practice
Six original Cambridge-style questions
sp2 carbons and the delocalised pi system of benzene, and the bond-length, hydrogenation and reactivity evidence against the Kekulé model.