Cambridge International AS & A Level · Topic 6.1
A-Level Maths 9709 / Topic 6.1 / AS & A Level

Swap a hard sum for an easy one.

Paper 6. A binomial with a huge \(n\) and a tiny \(p\) behaves like a Poisson, and a Poisson with a large mean behaves like a normal. Knowing when each swap is allowed, and how to correct for continuity, turns long calculations into short ones.

The key idea

If \(X \sim B(n, p)\) with \(n > 50\) and \(np < 5\), use \(X \approx \text{Po}(np)\). If \(X \sim \text{Po}(\lambda)\) with \(\lambda > 15\), use \(X \approx N(\lambda, \lambda)\): the variance equals the mean, and a continuity correction of \(0.5\) is needed because a discrete count is replaced by a continuous variable.

x = 15.5 1015202530 bars: Po(20) curve: N(20, 20) P(X ≤ 15) = 0.1565 (exact) ≈ P(Y < 15.5) = 0.1572
Fig. 1: Po(20) (bars, drawn to scale) and the normal curve N(20, 20). The teal bars are X ≤ 15; the approximating area stops at 15.5, half-way through the next bar
Section 01

Binomial to Poisson.

When \(n\) is large and \(p\) is small, successes are rare events scattered among many trials, which is exactly the Poisson picture. The mean \(np\) carries over and the variance \(np(1-p)\) is almost \(np\) because \(1 - p \approx 1\).

ExactConditionsApproximation
\(B(n, p)\)\(n > 50\) and \(np < 5\)\(\text{Po}(np)\)
\(B(n, p)\), \(p\) close to 1\(n > 50\) and \(n(1-p) < 5\)count failures: \(\text{Po}(n(1-p))\)
Worked example A rare defect
1.5% of bolts made by a machine are faulty. A random sample of 200 bolts is taken. Use a suitable approximation to find the probability that at most 2 are faulty.
  1. \(X \sim B(200, 0.015)\). Here \(n = 200 > 50\) and \(np = 3 < 5\), so use \(X \approx \text{Po}(3)\).
  2. \(\text{P}(X \le 2) \approx e^{-3}\left(1 + 3 + \dfrac{3^{2}}{2}\right) = 8.5e^{-3}\).
  3. \(= 0.4232\). (The exact binomial value is \(0.4215\), so the approximation is good.)
Answer: \(0.423\) (3 s.f.)
Worked example When \(p\) is close to 1
97% of eggs in a large batch are undamaged. A box of 80 eggs is chosen at random. Find, using an approximation, the probability that at least 78 eggs are undamaged.
  1. Undamaged eggs: \(B(80, 0.97)\), with mean 77.6. Neither approximation fits this directly.
  2. Count damaged eggs instead: \(D \sim B(80, 0.03)\), \(n > 50\), \(np = 2.4 < 5\), so \(D \approx \text{Po}(2.4)\).
  3. At least 78 undamaged means at most 2 damaged: \(\text{P}(D \le 2)\).
  4. \(= e^{-2.4}(1 + 2.4 + 2.88) = 6.28e^{-2.4} = 0.5697\).
Answer: \(0.570\) (3 s.f.)
Examiner trap

State the conditions with numbers: "\(n = 200 > 50\) and \(np = 3 < 5\)". Writing "\(n\) is large and \(p\) is small" with no values often loses the mark, and using \(\text{Po}(np(1-p))\) is wrong: the Poisson parameter is the mean, \(np\).

Section 02

Poisson to normal.

As \(\lambda\) grows, the Poisson bars become symmetric and bell-shaped (Fig. 1). For \(\lambda > 15\), use \(Y \sim N(\lambda, \lambda)\), remembering that the variance is \(\lambda\), so the standard deviation is \(\sqrt{\lambda}\).

Poisson eventIncludesNormal event
\(X \le 15\)15\(Y < 15.5\)
\(X < 15\)up to 14\(Y < 14.5\)
\(X \ge 25\)25 upwards\(Y > 24.5\)
\(X > 25\)26 upwards\(Y > 25.5\)
Worked example A lower tail
\(X \sim \text{Po}(20)\). Use a suitable approximation to find \(\text{P}(X \le 15)\).
  1. \(\lambda = 20 > 15\), so \(X \approx Y \sim N(20, 20)\).
  2. Continuity correction: \(\text{P}(X \le 15) \approx \text{P}(Y < 15.5)\).
  3. \(z = \dfrac{15.5 - 20}{\sqrt{20}} = -1.006\).
  4. \(\Phi(-1.006) = 1 - 0.8428 = 0.1572\).
Answer: \(0.157\) (3 s.f.); the exact Poisson value is \(0.1565\)
Worked example An upper tail
Requests reach a server at random at a mean rate of 20 per second. Find the approximate probability of more than 25 requests in a given second.
  1. \(X \sim \text{Po}(20)\), approximated by \(Y \sim N(20, 20)\).
  2. More than 25 means 26 or more, so \(\text{P}(Y > 25.5)\).
  3. \(z = \dfrac{25.5 - 20}{\sqrt{20}} = 1.230\).
  4. \(1 - \Phi(1.230) = 1 - 0.8907 = 0.1093\).
Answer: \(0.109\) (3 s.f.)
Worked example A two-sided range
\(X \sim \text{Po}(30)\). Find, approximately, \(\text{P}(25 \le X \le 35)\).
  1. \(Y \sim N(30, 30)\). Including 25 and 35 gives \(\text{P}(24.5 < Y < 35.5)\).
  2. \(z = \pm\dfrac{5.5}{\sqrt{30}} = \pm 1.004\).
  3. \(\Phi(1.004) - \Phi(-1.004) = 2(0.8423) - 1 = 0.6846\).
Answer: \(0.685\) (3 s.f.)
Your turn
\(X \sim \text{Po}(22)\). Use a normal approximation to find \(\text{P}(X < 19)\).
Examiner trap

The standard deviation of \(N(20, 20)\) is \(\sqrt{20}\), not 20. Dividing by 20 is the commonest error in this topic, closely followed by forgetting the continuity correction altogether.

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Which binomial distribution is best approximated by a Poisson distribution?

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\(X \sim \text{Po}(25)\). Which normal distribution approximates \(X\)?

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\(X \sim \text{Po}(40)\) is approximated by \(Y \sim N(40, 40)\). Which event replaces \(X < 30\)?

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Why is no continuity correction used when \(B(n, p)\) is approximated by \(\text{Po}(np)\)?

Section 03

Choosing the right approximation.

Check the parameters before choosing. Paper 6 questions often say "use a suitable approximation" and award a mark just for justifying the choice.

Examiner trap

Do not apply a continuity correction when approximating binomial by Poisson. Both are discrete, so \(\text{P}(X \le 2)\) stays \(\text{P}(X \le 2)\).

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\(X \sim B(120, 0.02)\). Which distribution is the most suitable approximation to \(X\)?

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\(X \sim \text{Po}(18)\). Using a normal approximation, find \(\text{P}(X \ge 20)\).

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\(X \sim B(250, 0.014)\). Use a suitable approximation to find \(\text{P}(X > 4)\).

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98% of seeds of a certain type germinate. 150 seeds are sown. Using a suitable approximation, find the probability that at most 146 seeds germinate.

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Six original Cambridge-style questions
Conditions, binomial to Poisson, Poisson to normal with continuity corrections, counting failures, and a call-centre problem.