Cambridge IGCSE · Topic 2.5
IGCSE Maths 0580 / Topic 2 / IGCSE

Keep the scales level.

An equation is a balance: do the same to both sides and it stays true. Solve equations with brackets and unknowns on both sides, form your own from a problem in words, and (Extended) clear fractions first.

The key idea

Whatever you do to one side of an equation, do to the other. Expand brackets, collect the unknown on one side and the numbers on the other, then divide. Check by substituting your answer back into the original equation.

Section 01

Solving on a balance.

In the lab pick an equation and press Next step one move at a time. Each step takes the same bags or blocks off both pans, so the balance stays level. Before each press, say what you would do next, then check against the lab.

Worked example Two steps
Solve \(3x + 4 = 10\).
  1. Subtract 4 from both sides: \(3x = 6\).
  2. Divide both sides by 3.
Answer: \(x = 2\)
Worked example Brackets on both sides
Solve \(4(2x - 3) = 2(x + 9)\).
  1. Expand: \(8x - 12 = 2x + 18\).
  2. Subtract \(2x\) from both sides: \(6x - 12 = 18\).
  3. Add 12 to both sides: \(6x = 30\).
  4. Divide by 6.
Answer: \(x = 5\) (check: \(4 \times 7 = 28\) and \(2 \times 14 = 28\))
Worked example A negative unknown term
Solve \(5 - 2x = 3(x + 7)\).
  1. Expand: \(5 - 2x = 3x + 21\).
  2. Add \(2x\) to both sides so the \(x\) term is positive: \(5 = 5x + 21\).
  3. Subtract 21: \(-16 = 5x\).
  4. Divide by 5: \(x = -\dfrac{16}{5}\).
Answer: \(x = -3.2\)
Your turn
Solve \(8 - 3(x - 2) = 2(x + 4)\).
Examiner trap

In \(8 - 3(x - 2)\), the \(-3\) multiplies the \(-2\) as well: \(-3 \times (-2) = +6\). Writing \(8 - 3x - 6\) is the most common slip on this type.

Section 02

Forming an equation.

Choose a letter for the unknown, write each quantity in terms of it, then use a fact you know (angles in a triangle add to 180°, a perimeter, a total) to make an equation.

Worked example Angles in a triangle
The angles of a triangle are \(x\)°, \((2x + 10)\)° and \((3x - 40)\)°. Find the size of the largest angle.
  1. Angles in a triangle add to 180°: \(x + 2x + 10 + 3x - 40 = 180\).
  2. Collect: \(6x - 30 = 180\), so \(6x = 210\) and \(x = 35\).
  3. The angles are \(35\)°, \(2(35) + 10 = 80\)° and \(3(35) - 40 = 65\)°.
Answer: The largest angle is 80°.
Worked example A perimeter
A rectangle is 3 cm longer than twice its width. Its perimeter is 42 cm. Find its length.
  1. Let the width be \(w\) cm; the length is \((2w + 3)\) cm.
  2. Perimeter: \(2(w + 2w + 3) = 42\), so \(6w + 6 = 42\).
  3. \(6w = 36\), \(w = 6\). Length \(= 2(6) + 3\).
Answer: 15 cm
Your turn
The sum of three consecutive whole numbers is 87. Find the numbers.
Examiner trap

Finding \(x\) is often not the end. Read the question again: it may ask for an angle, a length or an age built from \(x\).

Stage 1 · Learn

Check your understanding

Four quick checks. Each correct answer earns XP and records this skill on your profile.

Quick check+10 XP

Solve \(3x + 4 = 10\).

Quick check+10 XP

Solve \(5x = 2x + 12\).

Quick check+10 XP

Solve \(\dfrac{x}{3} - 2 = 5\).

Quick check+10 XP

I think of a number \(n\), double it and subtract 7. The answer is 15. Which equation is correct?

Section 03

Fractional equations (Extended).

Clear the fractions first. Multiply every term on both sides by the lowest common denominator; when the denominators contain \(x\), cross-multiply. Put brackets round each numerator.

Worked example Numerical denominators (Extended)
Solve \(\dfrac{x + 2}{2} + \dfrac{2x - 1}{3} = 1\).
  1. Multiply EVERY term by 6: \(3(x + 2) + 2(2x - 1) = 6\).
  2. Expand: \(3x + 6 + 4x - 2 = 6\), so \(7x + 4 = 6\).
  3. \(7x = 2\).
Answer: \(x = \dfrac{2}{7}\)
Worked example Algebraic denominators (Extended)
Solve \(\dfrac{5}{x + 1} = \dfrac{2}{x - 2}\).
  1. Cross-multiply: \(5(x - 2) = 2(x + 1)\).
  2. Expand: \(5x - 10 = 2x + 2\).
  3. \(3x = 12\).
Answer: \(x = 4\) (check: \(\dfrac{5}{5} = 1\) and \(\dfrac{2}{2} = 1\))
Your turn
(Extended) Solve \(\dfrac{2x + 1}{x} = 4\).
Examiner trap

Multiplying only the fractions by 6 and forgetting the 1 on the right gives \(7x + 4 = 1\). Every term, on both sides, must be multiplied.

Stage 2 · Exam

Exam-style questions

Unlocks once the four checks above are done. Worth more XP, written to IGCSE Paper 2 and Paper 4 standard.

Finish the four checks above to unlock the exam questions
Exam style+20 XP

Solve \(5 - 2x = 3(x + 7)\).

Exam style+20 XP

Solve \(4(2x - 3) = 2(x + 9)\).

Exam style+20 XP

The angles of a triangle are \(x\)°, \((2x + 10)\)° and \((3x - 40)\)°. What is the size of the largest angle?

Exam style+20 XP

(Extended) Solve \(\dfrac{x + 2}{2} + \dfrac{2x - 1}{3} = 1\).

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Go deeper · practice
Six original Cambridge-style questions
Two-step equations, brackets on both sides, forming equations from shapes and prices, and fractional equations (Extended).