Cambridge IGCSE · Topic 1.3
IGCSE Maths 0580 / Topic 1 / IGCSE

Undo the power.

Squaring and cubing build numbers up; square roots and cube roots take them back down. Know the squares to 15 and the key cubes by heart, then use a calculator with confidence for the rest.

The key idea

A root undoes a power: \(\sqrt{169} = 13\) because \(13^{2} = 169\), and \(\sqrt[3]{64} = 4\) because \(4^{3} = 64\). A square root of a positive number is taken as positive; a cube root keeps the sign, so \(\sqrt[3]{-125} = -5\).

4 4 4² = 16, √16 = 4 2 2³ = 8, ∛8 = 2
Fig. 1: a square of side 4 is made of 4² = 16 unit squares; a cube of edge 2 is made of 2³ = 8 unit cubes. The root recovers the side from the total
Section 01

Squares and square roots.

In the lab, slide \(n\) and watch the square grow as \(n^{2}\) unit squares; then switch to roots, type a number and see which two squares it lies between. Say each square aloud until you know 1 to 15 without the lab.

\(n\)123456789101112131415
\(n^{2}\)149162536496481100121144169196225
Worked example Recall
Write down the value of (a) \(\sqrt{169}\) (b) \(\sqrt{0.49}\).
  1. (a) \(13^{2} = 169\), so \(\sqrt{169} = 13\).
  2. (b) \(0.7^{2} = 0.49\) (since \(7^{2} = 49\) and \(0.7 \times 0.7\) has two decimal places).
Answer: (a) 13   (b) 0.7
Worked example Trapping a root
Without a calculator, find the two consecutive integers that \(\sqrt{50}\) lies between.
  1. Find the squares either side of 50: \(7^{2} = 49\) and \(8^{2} = 64\).
  2. \(49 < 50 < 64\), so \(\sqrt{49} < \sqrt{50} < \sqrt{64}\).
Answer: \(7 < \sqrt{50} < 8\) (and it is only just above 7)
Examiner trap

\(-3^{2}\) means \(-(3^{2}) = -9\), but \((-3)^{2} = 9\). On a calculator, put brackets round a negative number before squaring it.

Section 02

Cubes and cube roots.

You must recall the cubes of 1, 2, 3, 4, 5 and 10 and their cube roots. Unlike square roots, cube roots of negative numbers exist: a negative times a negative times a negative is negative.

\(n\)1234510
\(n^{3}\)1827641251000
Worked example Without a calculator
Work out \(5^{2} \times \sqrt[3]{8}\).
  1. \(5^{2} = 25\).
  2. \(\sqrt[3]{8} = 2\) because \(2^{3} = 8\).
  3. \(25 \times 2 = 50\).
Answer: 50
Worked example Negative and decimal cube roots
Write down (a) \(\sqrt[3]{-125}\) (b) \(\sqrt[3]{0.008}\).
  1. (a) \((-5)^{3} = -5 \times -5 \times -5 = -125\).
  2. (b) \(2^{3} = 8\), and \(0.2^{3} = 0.008\) (three decimal places).
Answer: (a) \(-5\)   (b) 0.2
Examiner trap

Cubing is not multiplying by 3: \(4^{3} = 4 \times 4 \times 4 = 64\), not 12. In the same way \(\sqrt[3]{27} = 3\), not 9.

Stage 1 · Learn

Check your understanding

Four quick checks. Each correct answer earns XP and records this skill on your profile.

Quick check+10 XP

Write down \(\sqrt{144}\).

Quick check+10 XP

Work out \(4^{3}\).

Quick check+10 XP

Write down \(\sqrt[3]{-27}\).

Quick check+10 XP

Which of these lies between 6 and 7?

Section 03

Other powers and roots, and the calculator.

\(2^{5} = 2 \times 2 \times 2 \times 2 \times 2 = 32\), so the fifth root of 32 is 2: \(\sqrt[5]{32} = 2\). For harder values use the calculator's \(x^{\square}\) and \(\sqrt[\square]{\ }\) keys, and put brackets round anything under a root sign that has more than one term.

Worked example Roots of a calculation
Work out \(\sqrt{12.5^{2} - 3.5^{2}}\).
  1. Work out under the root first: \(12.5^{2} = 156.25\) and \(3.5^{2} = 12.25\).
  2. \(156.25 - 12.25 = 144\).
  3. \(\sqrt{144} = 12\).
Answer: 12
Worked example Higher powers
Work out (a) \(3^{4}\) (b) \(\sqrt[4]{81}\) (c) \(1.3^{3}\).
  1. (a) \(3 \times 3 \times 3 \times 3 = 81\).
  2. (b) The fourth root undoes the fourth power, and \(3^{4} = 81\).
  3. (c) \(1.3 \times 1.3 = 1.69\), then \(1.69 \times 1.3 = 2.197\).
Answer: (a) 81   (b) 3   (c) 2.197
Your turn
Work out \(\sqrt{6.4 + 3.6^{2}}\).
Examiner trap

\(\sqrt{12.5^{2} - 3.5^{2}}\) is NOT \(12.5 - 3.5 = 9\). A root does not split over a plus or minus sign; work out the whole expression underneath first.

Stage 2 · Exam

Exam-style questions

Unlocks once the four checks above are done. Worth more XP, written to IGCSE Paper 2 and Paper 4 standard.

Finish the four checks above to unlock the exam questions
Exam style+20 XP

Without a calculator, work out \(5^{2} \times \sqrt[3]{8}\).

Exam style+20 XP

Work out \(\sqrt{13^{2} - 5^{2}}\).

Exam style+20 XP

Use your calculator to work out \(\dfrac{\sqrt{20.25} + 1.5^{3}}{2^{4}}\). Give your answer correct to 3 significant figures.

Exam style+20 XP

A cube has volume 343 cm3. Find its total surface area.

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Go deeper · practice
Six original Cambridge-style questions
Recall of squares and cubes, negative and decimal roots, calculator work with roots, comparing roots without a calculator, and a water-tank problem.