Cambridge IGCSE · Topic 1.8
IGCSE Maths 0580 / Topic 1 / IGCSE

Big and small, one shape.

The mass of the Earth and the width of an atom are both easy to write once every number has the same shape: a number from 1 up to 10, times a power of ten.

The key idea

A number in standard form is \(A \times 10^{n}\), where \(1 \le A < 10\) and \(n\) is an integer. The power \(n\) counts how many places the digits move: positive for large numbers, negative for small ones.

340000 point moves 5 places left 3.4 × 10 5 1 ≤ 3.4 < 10 340 000 = 3.4 × 100 000 = 3.4 × 10⁵
Fig. 1: the decimal point moves 5 places to make a number between 1 and 10, so the power is 5
Section 01

One number between 1 and 10.

Type a number into the lab and watch the decimal point hop until exactly one non-zero digit sits in front of it. Count the hops: that count is the power of ten. Then try a tiny number such as 0.000 52 and see the power turn negative.

Worked example Into standard form
Write (a) \(4\,060\,000\) and (b) \(0.000\,089\) in standard form.
  1. (a) Put the point after the first non-zero digit: \(4.06\).
  2. Count the places from \(4.06\) back to \(4\,060\,000\): the point moves 6 places, and the number is large, so the power is \(+6\).
  3. (b) The first non-zero digit is 8, so \(A = 8.9\).
  4. From \(0.000\,089\) to \(8.9\) the point moves 5 places right; the number is small, so the power is \(-5\).
Answer: (a) \(4.06 \times 10^{6}\)   (b) \(8.9 \times 10^{-5}\)
Worked example Out of standard form
Write \(7.25 \times 10^{-3}\) as an ordinary number.
  1. A power of \(-3\) means divide by \(10^{3} = 1000\), so the point moves 3 places left.
  2. \(7.25 \to 0.725 \to 0.0725 \to 0.007\,25\).
Answer: \(0.007\,25\)
Examiner trap

\(34 \times 10^{5}\) is a correct number but it is NOT in standard form, because \(34\) is not less than 10. Examiners give no mark for it. Fix it to \(3.4 \times 10^{6}\).

Section 02

Comparing and ordering.

To order numbers in standard form, compare the powers first. Only when two powers are equal do you compare the front numbers.

NumbersCompareLarger
\(9.1 \times 10^{3}\) and \(1.2 \times 10^{4}\)powers 3 and 4\(1.2 \times 10^{4}\)
\(6.5 \times 10^{-2}\) and \(8 \times 10^{-3}\)powers \(-2\) and \(-3\): \(-2\) is bigger\(6.5 \times 10^{-2}\)
\(2.7 \times 10^{5}\) and \(3.1 \times 10^{5}\)same power, so 2.7 and 3.1\(3.1 \times 10^{5}\)
Examiner trap

With negative powers, the bigger-looking power is the smaller number: \(10^{-5}\) is a hundred times SMALLER than \(10^{-3}\).

Stage 1 · Learn

Check your understanding

Four quick checks. Each correct answer earns XP and records this skill on your profile.

Quick check+10 XP

Which of these is written in standard form?

Quick check+10 XP

Write \(37\,000\) in standard form.

Quick check+10 XP

Write \(0.0061\) in standard form.

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Which number is the largest?

Section 03

Calculating in standard form.

For multiplying and dividing, deal with the front numbers and the powers of ten separately, using the laws of indices. For adding and subtracting, first write both numbers with the same power (or as ordinary numbers). Always tidy the answer so the front number is between 1 and 10.

Worked example Multiply without a calculator (Extended)
Work out \((6 \times 10^{4}) \times (5 \times 10^{-7})\). Give your answer in standard form.
  1. Front numbers: \(6 \times 5 = 30\).
  2. Powers: \(10^{4} \times 10^{-7} = 10^{4 + (-7)} = 10^{-3}\).
  3. So the product is \(30 \times 10^{-3}\), which is not yet standard form.
  4. \(30 = 3 \times 10^{1}\), so \(30 \times 10^{-3} = 3 \times 10^{1} \times 10^{-3} = 3 \times 10^{-2}\).
Answer: \(3 \times 10^{-2}\)
Worked example Divide
Work out \(\dfrac{4.8 \times 10^{9}}{1.6 \times 10^{3}}\).
  1. Front numbers: \(4.8 \div 1.6 = 3\).
  2. Powers: \(10^{9} \div 10^{3} = 10^{9-3} = 10^{6}\).
Answer: \(3 \times 10^{6}\)
Worked example Add (Extended)
Work out \(2.4 \times 10^{5} + 6 \times 10^{4}\).
  1. Make the powers match: \(6 \times 10^{4} = 0.6 \times 10^{5}\).
  2. Add the front numbers: \(2.4 + 0.6 = 3.0\).
Answer: \(3 \times 10^{5}\) (check: \(240\,000 + 60\,000 = 300\,000\))
Your turn
Work out \((2 \times 10^{-3})^{2}\). Give your answer in standard form.
Examiner trap

You cannot add powers when adding numbers: \(2 \times 10^{5} + 3 \times 10^{4}\) is NOT \(5 \times 10^{9}\). Index laws are for multiplying and dividing only.

Section 04

Standard form on a calculator.

On Paper 3 and Paper 4 you may use the calculator's \(\times 10^{x}\) (or EXP) key. Read the display carefully and write the answer properly.

Stage 2 · Exam

Exam-style questions

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Work out \((3 \times 10^{5}) \times (4 \times 10^{-2})\), giving your answer in standard form.

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Work out \(\dfrac{9 \times 10^{4}}{3 \times 10^{-2}}\).

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Work out \(5.6 \times 10^{3} - 8 \times 10^{2}\), giving your answer in standard form.

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Light travels \(3 \times 10^{8}\) metres per second. How far does it travel in \(5 \times 10^{2}\) seconds?

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Go deeper · practice
Six original Cambridge-style questions
Converting both ways, ordering, the four operations without a calculator, and a calculator problem on the speed of light.