Cambridge IGCSE · Topic 1.1
IGCSE Maths 0580 / Topic 1 / IGCSE

Every number has a family.

Natural numbers, integers, primes, squares, cubes, factors, multiples, rational and irrational numbers and reciprocals: the vocabulary every other topic in IGCSE Mathematics is written in.

The key idea

Every whole number greater than 1 can be written as a product of primes in exactly one way. Write both numbers as prime products: the HCF takes the primes they share (lowest powers), the LCM takes every prime that appears (highest powers).

7289 4 222 33 72 = 2³ × 3² stop at primes
Fig. 1: a factor tree for 72. Split until every branch ends in a prime (circled), then collect them: 72 = 2 × 2 × 2 × 3 × 3
Section 01

Naming the numbers.

In the lab, pick two numbers and watch their multiples light up on the 1 to 100 grid; then switch to factors and step through the sieve until only the primes are left. Notice which numbers are never lit: they are the primes.

Worked example Sorting a list
From the list \(\ 1,\ 2,\ 9,\ 15,\ 27,\ 31,\ 64\ \) write down (a) the prime numbers (b) the square numbers (c) the cube numbers.
  1. (a) Test each number for factors other than 1 and itself: 9, 15, 27 and 64 all have extra factors; 1 has only one factor so it is not prime.
  2. So the primes are 2 and 31.
  3. (b) \(1 = 1^{2}\), \(9 = 3^{2}\), \(64 = 8^{2}\).
  4. (c) \(1 = 1^{3}\), \(27 = 3^{3}\), \(64 = 4^{3}\).
Answer: (a) 2, 31   (b) 1, 9, 64   (c) 1, 27, 64
Worked example Numbers and words
(a) Write six billion in figures. (b) Write 10 007 in words. (c) Write 2 040 500 in words.
  1. (a) One billion is a thousand million, \(1\,000\,000\,000\) (9 zeros).
  2. (b) Split into thousands and the rest: 10 thousand and 7.
  3. (c) Split into groups of three from the right: 2 | 040 | 500, so 2 million, 40 thousand, 500.
Answer: (a) 6 000 000 000   (b) ten thousand and seven   (c) two million, forty thousand, five hundred
Examiner trap

1 is not a prime number, and 2 is the only even prime. A list of primes starting \(1, 3, 5, 7, 9\) loses marks twice: 1 and 9 are not prime, and 2 is missing.

Section 02

Prime factors.

Open the prime factors tab, choose a number and press Next step: the lab divides by the smallest prime that works, again and again, until 1 is left. The primes it divided by are the prime factors.

Worked example Product of prime factors
Write 360 as a product of its prime factors, using index notation.
  1. Divide by the smallest prime that goes in: \(360 \div 2 = 180\), \(180 \div 2 = 90\), \(90 \div 2 = 45\).
  2. 2 no longer goes into 45, so try 3: \(45 \div 3 = 15\), \(15 \div 3 = 5\).
  3. 5 is prime: \(5 \div 5 = 1\). Stop.
  4. Collect the divisors: three 2s, two 3s and one 5.
Answer: \(360 = 2^{3} \times 3^{2} \times 5\)
Examiner trap

\(72 = 8 \times 9\) is true, but it is not a product of PRIMES: 8 and 9 both split further. Keep going until every factor is prime, then use index notation: \(2^{3} \times 3^{2}\).

Stage 1 · Learn

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Which of these numbers is prime?

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Which of these numbers is irrational?

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What is the reciprocal of 0.2?

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Which is 72 written as a product of its prime factors?

Section 03

HCF and LCM.

The highest common factor (HCF) is the biggest number that divides into both; the lowest common multiple (LCM) is the smallest number both divide into. Prime factors give both at once.

\(84\)\(90\)HCF: shared primes, lowest powerLCM: all primes, highest power
2\(2^{2}\)\(2\)\(2\)\(2^{2}\)
3\(3\)\(3^{2}\)\(3\)\(3^{2}\)
5-\(5\)-\(5\)
7\(7\)--\(7\)
Worked example HCF and LCM from prime factors
Find the HCF and the LCM of 84 and 90.
  1. \(84 = 2^{2} \times 3 \times 7\) and \(90 = 2 \times 3^{2} \times 5\).
  2. HCF: the primes in both are 2 and 3; take the lower power of each: \(2 \times 3 = 6\).
  3. LCM: every prime that appears, at its higher power: \(2^{2} \times 3^{2} \times 5 \times 7\).
  4. \(4 \times 9 \times 5 \times 7 = 1260\).
Answer: HCF \(= 6\), LCM \(= 1260\)
Worked example LCM in context
Bus A leaves the station every 12 minutes and bus B every 18 minutes. Both leave at 08:00. When do they next leave together?
  1. They leave together after a time that is a multiple of both 12 and 18: the LCM.
  2. \(12 = 2^{2} \times 3\), \(18 = 2 \times 3^{2}\), so LCM \(= 2^{2} \times 3^{2} = 36\) minutes.
  3. 08:00 plus 36 minutes.
Answer: 08:36
Your turn
Find the HCF and the LCM of 48 and 180.
Examiner trap

Do not mix the rules. The HCF can never be bigger than the smaller number, and the LCM can never be smaller than the bigger one. If your HCF of 84 and 90 is 1260, you have swapped them.

Section 04

Rational, irrational and reciprocals.

A rational number can be written as a fraction \(\dfrac{a}{b}\) of two integers (\(b \ne 0\)). Terminating decimals, recurring decimals and square roots of square numbers are all rational. An irrational number cannot be written as a fraction: its decimal goes on for ever with no repeating pattern.

Worked example Reciprocals
Find the reciprocal of (a) 2.5 (b) \(\dfrac{3}{4}\) (c) \(1\dfrac{2}{3}\).
  1. (a) \(2.5 = \dfrac{5}{2}\), so the reciprocal is \(\dfrac{2}{5} = 0.4\).
  2. (b) Turn the fraction upside down: \(\dfrac{4}{3}\).
  3. (c) First make it improper: \(1\dfrac{2}{3} = \dfrac{5}{3}\), then turn it over: \(\dfrac{3}{5}\).
Answer: (a) 0.4   (b) \(\dfrac{4}{3}\)   (c) \(\dfrac{3}{5}\)
Examiner trap

\(\sqrt{9}\) looks irrational because it has a root sign, but \(\sqrt{9} = 3\), which is rational. Always simplify first. And the reciprocal of \(1\dfrac{2}{3}\) is not \(1\dfrac{3}{2}\): convert to an improper fraction before turning it over.

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Find the highest common factor (HCF) of 60 and 84.

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Two lights flash together at exactly 9 pm. One flashes every 15 seconds, the other every 20 seconds. After how many seconds do they next flash together?

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\(P = 2^{3} \times 3 \times 5^{2}\) and \(Q = 2^{2} \times 3^{2} \times 5\). Find the lowest common multiple of \(P\) and \(Q\).

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Which list contains only irrational numbers?

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Six original Cambridge-style questions
Numbers in words, spotting primes, squares and cubes, prime factorisation, HCF and LCM, rational numbers and reciprocals, and a sharing problem.