Cambridge IGCSE · Topic 9.6
IGCSE Maths 0580 / Topic 9 / IGCSE

Running totals, smooth curve.

Extended. A cumulative frequency curve turns a grouped frequency table into a graph you can read: the median, the quartiles, any percentile, and how many values lie above or below any point.

The key idea

Cumulative frequency is a running total. Plot each total at the UPPER boundary of its class and join with a smooth curve. For \(n\) values, read across at \(\dfrac{n}{4}\), \(\dfrac{n}{2}\) and \(\dfrac{3n}{4}\) for the lower quartile, median and upper quartile.

0 10 20 30 40 50 60 0 10 20 30 40 50 60 70 80 Time (minutes) Cumulative frequency LQ = 20 (read at 20) median ≈ 28 (at 40) UQ ≈ 38 (at 60)
Fig. 1: cumulative frequency curve for the times of 80 people, drawn to scale from the table in the first worked example. Reading across at 20, 40 and 60 gives LQ = 20, median ≈ 28 and UQ ≈ 38 minutes.
Section 01

Building the curve.

In the lab, add up the frequencies as you go to fill the cumulative frequency column. Then watch where each cross is plotted: at the upper end of its class, not the middle. Change a frequency and see the curve and every reading move.

Worked example From a frequency table to a curve
The times, \(t\) minutes, taken by 80 people to finish a puzzle are shown. Make a cumulative frequency table and list the points to plot.
TimeFrequency
\(0 < t \le 10\)6
\(10 < t \le 20\)14
\(20 < t \le 30\)24
\(30 < t \le 40\)20
\(40 < t \le 50\)12
\(50 < t \le 60\)4
  1. Running totals: \(6\), \(6 + 14 = 20\), \(20 + 24 = 44\), \(44 + 20 = 64\), \(64 + 12 = 76\), \(76 + 4 = 80\).
  2. Check: the last total, 80, is the number of people.
  3. Plot at the upper boundaries: (10, 6), (20, 20), (30, 44), (40, 64), (50, 76), (60, 80), starting from (0, 0).
  4. Join the crosses with a smooth curve (Fig. 1).
Answer: cf: 6, 20, 44, 64, 76, 80; points (0, 0), (10, 6), (20, 20), (30, 44), (40, 64), (50, 76), (60, 80)
Examiner trap

Plotting at the midpoints (5, 15, 25, ...) shifts the whole curve 5 minutes to the left and every reading is wrong. The cf belongs to the upper boundary.

Section 02

Median, quartiles and IQR.

Every reading is the same move: start on the cumulative frequency axis, go across to the curve, then down to the horizontal axis. With a large data set, use \(\dfrac{n}{2}\) for the median, not \(\dfrac{n+1}{2}\).

MeasureRead across atFor \(n = 80\)
Lower quartile\(\dfrac{n}{4}\)20
Median\(\dfrac{n}{2}\)40
Upper quartile\(\dfrac{3n}{4}\)60
Worked example Read the curve
Use the curve in Fig. 1 to estimate the median, the quartiles and the interquartile range of the times.
  1. Median: across from 40 to the curve, then down: about 28 minutes.
  2. Lower quartile: across from 20: 20 minutes (the point (20, 20) is on the curve).
  3. Upper quartile: across from 60: about 38 minutes.
  4. IQR \(= 38 - 20 = 18\) minutes.
Answer: Median \(\approx 28\) min, LQ = 20 min, UQ \(\approx 38\) min, IQR \(\approx 18\) min
Examiner trap

The IQR is the difference of two TIMES read from the horizontal axis (\(38 - 20\)), not the difference of the cumulative frequencies (\(60 - 20 = 40\)).

Stage 1 · Learn

Check your understanding

Four quick checks. Each correct answer earns XP and records this skill on your profile.

Quick check+10 XP

Frequencies 3, 7, 10, 5. What is the third cumulative frequency?

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Where is the cumulative frequency for the class \(20 < t \le 30\) plotted?

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A cumulative frequency curve shows 60 values. At what cumulative frequency do you read the median?

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From a curve, LQ = 34 kg and UQ = 52 kg. What is the interquartile range?

Section 03

Percentiles and how many questions.

The \(p\)th percentile is read across at \(p\%\) of \(n\). Questions that ask how many values are above a point need one extra step: the curve gives how many are BELOW, so subtract from the total.

Worked example Percentile
Use Fig. 1 to estimate the 90th percentile of the times.
  1. \(90\%\) of 80 \(= 72\).
  2. Across from 72 to the curve, then down: about 46 minutes.
Answer: About 46 minutes: 90% of the people finished within 46 minutes.
Worked example More than a value
Use Fig. 1 to estimate how many people took more than 45 minutes.
  1. Up from 45 on the time axis to the curve, then across: cf \(\approx 71\). So about 71 people took 45 minutes or less.
  2. More than 45 minutes: \(80 - 71 = 9\) people.
Answer: About 9 people
Your turn
A cumulative frequency curve for the marks of 200 students gives 64 marks at the 80th percentile. How many students scored more than 64?
Examiner trap

'How many took MORE than 45 minutes' is the total minus the reading. Writing 71, the number who took 45 minutes or less, is the most common lost mark on this topic.

Stage 2 · Exam

Exam-style questions

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Exam style+20 XP

Use the curve in Fig. 1 (times of 80 people) to estimate the interquartile range.

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Use the curve in Fig. 1 to estimate how many people took more than 45 minutes.

Exam style+20 XP

A class \(20 < t \le 30\) has frequency 24 and cumulative frequency 44. Which point is plotted on the cumulative frequency diagram?

Exam style+20 XP

The marks of 200 students are shown on a cumulative frequency curve. The 80th percentile is 64 marks. How many students scored more than 64 marks?

Skill unlocked

Cumulative frequency, read.

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Go deeper · practice
Six original Cambridge-style questions
Cumulative frequency tables, plotting at upper boundaries, reading the median, quartiles, IQR and percentiles, and 'how many more than' questions.