A2 Level · Topic 19.2
A-Level 9702 / Topic 19 / A2

The energy in the field.

Charging a capacitor does work against the charge already there, and that work is stored as energy. A graph makes the factor of one half obvious.

The key idea

The energy stored in a capacitor is the area under the graph of voltage against charge, a triangle, so W = ½QV. Using Q = CV this is also ½CV² or ½Q²/C.

area = ½QV V Q
Fig. 1 — The area under the p.d.–charge graph is the energy stored: W = ½QV = ½CV²
Section 01

Reading energy off a graph.

Vary C and V and watch the shaded triangle under the V-Q line. Its area, ½QV, is the stored energy, and it grows with the square of the voltage.

Section 02

Three forms, one energy.

Because the voltage rises from zero to V as the charge builds up, the average voltage is ½V and the energy is ½QV, not QV. Substituting Q = CV gives the equivalent forms ½CV² and ½Q²/C. Energy depends on the square of the voltage, so doubling V quadruples the energy.

Stage 1 · Learn

Check what the sim just showed you

Four quick checks on the energy stored and where the factor of ½ comes from. Each correct answer earns XP and lights this skill on your star map.

Quick check+10 XP

The energy stored in a capacitor equals the area under a graph of:

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The energy stored in a capacitor can be written as:

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Doubling the voltage on a capacitor changes the energy stored by a factor of:

Quick check+10 XP

The factor of ½ in W = ½QV arises because:

Examiner trap

The energy is ½QV, not QV, because the voltage climbs from zero to V as charge accumulates (the average is ½V, giving a triangle). Energy depends on the square of the voltage, so doubling V gives four times the energy, and the three forms ½QV, ½CV² and ½Q²/C are all equal.

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Energy stored in a capacitor

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Original Paper 4 structured questions spanning every lesson in this topic, with full worked solutions.