Revision notes · Topic 5 of 11 · AS

Work, energy and power

One conservation law doing all the work: from W = Fs cos θ to P = Fv.

Syllabus 5.1 to 5.2 Tier AS Level Prepared by the TheLucidSTEM team

§ 5.1 Energy conservation

Key ideas
  • Work done W = Fs cos θ, where θ is the angle between the force and the displacement; work transfers energy.
  • Energy is conserved: never created or destroyed, only transferred between stores or converted in form.
  • Efficiency = useful output ÷ total input, as a ratio or a percentage.
Equations
W = F s cos θwork = force × displacement × cos(angle between them)J
efficiency = useful / totaluseful energy or power out ÷ total inno unit
F θ F cos θ displacement s
Fig. 1 · Only the component of F along the motion does work: W = Fs cos θ; the perpendicular component does none at all.
Watch out: a force perpendicular to the motion does zero work, however large it is: cos 90° = 0. The weight of a satellite in circular orbit does no work on it.

§ 5.2 Gravitational PE and kinetic energy

Key ideas
  • Kinetic energy Ek = ½mv², derived from W = Fs with F = ma and v² = u² + 2as.
  • Gravitational potential energy change ΔEp = mgΔh, from the work mg does over a height change Δh.
  • For a falling object with negligible resistance, Ep transfers to Ek joule for joule: the total stays constant.
  • Power is the rate of doing work, P = W/t; for a constant force at steady speed, P = Fv.
Equations
Ek = ½ m v²kinetic energy of a moving massJ
ΔEp = m g Δhchange in gravitational potential energyJ
P = W / tpower = rate of doing workW
P = F vpower = force × velocity at constant speedW
energy height fallen total energy constant Ek Ep
Fig. 2 · The energy trade during a fall: Ep drains at exactly the rate Ek fills, so the two lines mirror each other beneath the constant total.
Watch out: the v in Ek = ½mv² is squared, so doubling speed quadruples kinetic energy. Equating mgΔh to ½mv² needs resistance to be negligible: say so when you use it.