IGCSE 0625 / Section 1.4 / Core

The volume that the water gives away.

A regular block surrenders its volume to a ruler. An odd shaped stone will not, so we let it push water aside instead. The water it displaces is exactly equal to its volume, as long as you account for where the water started.

The key idea

For a regular solid, calculate the volume from its measured dimensions. For an irregular solid, use displacement: the volume is the rise in level in a measuring cylinder, or the water collected from a Eureka can. In every case, ρ = m / V.

Key principle · in exam words

Displacement method: the volume of an irregular solid equals the volume of liquid it displaces.

V = final level − initial level

Then combine with the mass to get the density, ρ = m / V.

Section 01

Let the water measure it.

Lower the solid into the measuring cylinder and read the level before and after. The volume of the solid is the difference between the two readings, never the final reading alone.

Stage 1 · Learn

Check the measuring methods

Four quick checks on regular shapes, displacement, and the readings. Each correct answer earns XP and lights this skill on your star map.

Quick check+10 XP

The volume of a regular cuboid block is found by...

Quick check+10 XP

To find the volume of a small irregular stone, the best method is...

Quick check+10 XP

A stone is lowered into a measuring cylinder. The water rises from 50 cm³ to 80 cm³. The volume of the stone is...

Quick check+10 XP

When an object is lowered into a full displacement (Eureka) can, the volume of water that overflows equals...

Section 02

Two routes to a volume.

 Regular solidIrregular solid
How to get the volumemeasure the dimensionsmeasure the liquid it displaces
ExampleV = l × w × h for a blockrise in a measuring cylinder, or a Eureka can
Thenfind the mass on a balance, and use ρ = m / V
Worked example

A stone of mass 90 g is lowered into a measuring cylinder. The water level rises from 40 cm³ to 70 cm³. Find the density of the stone.

Step 1 · Volume from the riseV = 70 − 40 = 30 cm³
Step 2 · Density from ρ = m / Vρ = 90 / 30 = 3.0 g/cm³
Step 3 · AnswerThe density is 3.0 g/cm³. Note that dividing by the full 70 cm³ would have given a wrong, smaller value.
Examiner trap

When using a single measuring cylinder, the classic error is dividing the mass by the whole final reading. That includes the water that was already there. The volume of the solid is only the rise in level, the final reading minus the initial reading. Forgetting to subtract the initial volume gives a density that is far too small.

Stage 2 · Exam

Exam-style questions

Unlocks once the four checks above are done. Worth more XP, written in the style of Paper 1.

Finish the four checks above to unlock the exam questions
Exam style+20 XP

A stone of mass 90 g is lowered into a cylinder and the water rises from 40 cm³ to 70 cm³. The density of the stone is...

Exam style+20 XP

Using those readings, a student divides 90 g by 70 cm³ and gets the wrong density. The mistake is that they...

Exam style+20 XP

A rectangular block measures 2.0 cm by 3.0 cm by 5.0 cm and has a mass of 120 g. Its density is...

Skill unlocked

Measuring density, mastered.

This skill is now lit gold on your star map. That completes the density topic.

-Rank -Level -Score -Topics
Go deeper · practice
Six original Cambridge-style questions
Volume of a regular solid from its dimensions, volume of an irregular solid by displacement, the rise-in-level reading, and the ρ = m / V calculation. Attempt each, then reveal the worked solution.
Stage 3 · master the unit
Motion, forces and energy challenge
Mixed questions across the whole unit, each one worth XP. Start this only when you feel confident across every topic in the unit, not just density.
Start the unit challenge →