IGCSE 0625 / Section 1.2 / Core

The shape of a journey.

A graph turns a journey into a picture you can read at a glance. On a distance-time graph the gradient is the speed; on a speed-time graph the gradient is the acceleration and the area underneath is the distance. Confusing those two graphs is where marks easily slip away.

The Key Idea

On a distance-time graph, the gradient (slope) is the speed. On a speed-time graph, the gradient is the acceleration and the area under the line is the distance travelled.

SECTION 01

The area is the distance.

For a speed that changes, you cannot just multiply the final speed by the total time. You must find the actual area under the line, splitting it into triangles and rectangles. Adjust the asymmetrical journey below and compare the correct area with that tempting shortcut.

SECTION 02

Reading each graph.

On the graphDistance-time graphSpeed-time graph
Gradientthe speedthe acceleration
Horizontal linestationary (not moving)constant speed (no acceleration)
Area under linehas no physical meaningthe distance travelled
Curve getting steeperspeeding upincreasing acceleration
time distance fast slow stationary
On a distance-time graph, a steeper line means a higher speed; a flat line means the object is stationary.
The classic speed-time graph error

When the speed is changing, the distance is not the final speed multiplied by the final time. That treats the whole graph as one massive rectangle. The distance is the area under the line, found by splitting it into triangles and rectangles and adding them. Use area = ½ × base × height for each triangle and length × width for each rectangle.

Worked Example

A car accelerates from rest to 20 m/s in 8.0 s, holds 20 m/s for 12 s, then brakes to rest in 5.0 s. Find the total distance travelled.

Step 1 : Speeding up (triangle) area = ½ × 8.0 × 20 = 80 m
Step 2 : Steady speed (rectangle) area = 20 × 12 = 240 m
Step 3 : Slowing down (triangle) area = ½ × 5.0 × 20 = 50 m
Step 4 : Add the areas total distance = 80 + 240 + 50 = 370 m. The shortcut 20 × 25 = 500 m would have been wrong.
Practice this topic →
Six original Cambridge-style questions.
Reading distance-time and speed-time graphs, gradient as speed and as acceleration, the area under a speed-time graph as distance, and describing a journey. Attempt each, then reveal the worked solution.