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Lesson pack · IGCSE Maths 0580 · 2.1 · IGCSE

Algebraic notation and substitution

Letters that stand for numbers. A letter in algebra is a number you have not met yet.

Student lesson Lab, full screen
At a glance

The shape of the lesson

Topic
Algebra and graphs
Syllabus reference
Cambridge IGCSE Mathematics 0580, 2.1
Level
IGCSE
Duration
45 minutes, lab-led; stretches to a 60 minute block (see the contingency notes)
Position in topic
Lesson 1 of 22 in Algebra and graphs; leads into Expanding brackets and simplifying
Central model
A letter stands for a number.
Cooperative structure
Assessment
Stage 1 check and the exam-style plenary from the student lesson, plus the worksheet as the exit task
Learning objectives

By the end of the lesson, learners can

Section by section
  • How algebra is written: Open the lab on Substitution, pick a formula and drag the sliders for each letter.
  • Substituting safely: Replace every letter with its value, and put each value in brackets, especially negative numbers.
  • Formulas in context: A formula is a rule written in algebra.
Key points to leave on the board
  • Notation: \(3a = 3 \times a\), \(ab = a \times b\), \(3a^{2} = 3 \times a^{2}\).
  • Words to algebra: if something happens first, it may need a bracket: \(3(n + 5)\).
  • Substitute: write each value in brackets, especially negatives.
  • Order: brackets, powers, multiply/divide, add/subtract.
  • Check signs: minus a negative is plus; a negative squared is positive.
The core visual model

One picture every idea returns to

A letter stands for a number. To substitute, replace each letter with its value in brackets, then follow the order of operations: brackets, then powers, then multiply and divide, then add and subtract.

Lesson sequence

Forty-five minutes, phase by phase

TimePhaseWhat happens in the roomGrouping
0 to 5 minHook: predictOpen with the question in the title, Letters that stand for numbers.. A letter in algebra is a number you have not met yet.Whole class, then pairs
5 to 13 minTeach and check: How algebra is writtenOpen the lab on Substitution, pick a formula and drag the sliders for each letter. Project tab 1 of the lab (Algebra lab, substitute and simplify) and let a student drive it while the class predicts. Model the worked example Words into algebra on the board, one line at a time.Whole class, then pairs
13 to 21 minTeach and check: Substituting safelyReplace every letter with its value, and put each value in brackets, especially negative numbers. Model the worked example Negative values on the board, one line at a time. Your turn: Find the value of \(\dfrac{p^{2} - q}{2p}\) when \(p = -4\) and \(q = 6\).Pairs
21 to 30 minTeach and check: Formulas in contextA formula is a rule written in algebra. Model the worked example Writing and using a formula on the board, one line at a time. Your turn: Use \(F = \dfrac{9C}{5} + 32\) to convert \(-15\)°C into degrees Fahrenheit.Numbered Heads Together
30 to 36 minCheckThe four Stage 1 questions from the student lesson, answered on mini whiteboards or by show of fingers. Re-teach the one most get wrong.Individual, then whole class
36 to 43 minPlenaryThe exam-style questions from Stage 2, one at a time: thirty seconds alone, then a random call. The feedback lines in the key give the examiner's wording.Individual, random call
43 to 45 minExit and homeworkSet the worksheet below (6 questions, 15 marks). Learners self-assess against the objectives before they leave.Individual
Timing and contingency

Protect the parts that carry the learning

The sequence carries about fifty minutes of material, so the lab is driven by one student while the class predicts rather than explored freely. Times are a guide.

Protected: the check at 30 minutes. It is the only individual read on whether the key idea landed, and it is not cut.

Cut first if the build overruns: the last check in Formulas in context, never the check or the plenary.

In a 60 minute block: run worksheet questions 1 to 3 in class as a Rally Coach set and model both the hardest worked example and its check live.

Running the cooperative task

Numbered Heads Together

Teams of four number off. Put up a question, give the team time to make sure every member can answer, then call a number: that student answers for the team, so nobody can leave the thinking to someone else.

The full structure, with its variations and the other twelve, is on the cooperative-learning page.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
\(n(n + 1)\) is the product of two consecutive numbers, but not necessarily even ones.Writing \(2n\) guarantees the number is even.
\(2x^{2}\) means \(2 \times x^{2}\), not \((2x)^{2}\).With \(x = -3\): \(2x^{2} = 18\) but \((2x)^{2} = 36\). And a calculator reads \(-3^{2}\) as \(-9\): type \((-3)^{2}\) with the brackets.
Money answers need two decimal places: $127.5 should be written $127.50.Return to Formulas in context: ask a pair to state the correct version and show it on the lab before moving on.
Worksheet

Algebraic notation and substitution: worksheet

6 questions, 15 marks. Written in the style of the papers; no past paper question is reproduced.

NameClassDate
Q1 · recall[2 marks]

Write an expression for (a) 7 less than \(y\) (b) \(x\) divided by 4, then add 3.

Q2 · calculation[3 marks]

Without a calculator, find the value of each expression when \(a = 5\) and \(b = -3\).

(a) \(a - b\)   (b) \(ab^{2}\)   (c) \(\dfrac{a + b}{a - b}\)

Q3 · calculation[2 marks]

The time, \(T\) seconds, for one swing of a pendulum of length \(l\) metres is \(T = 2\pi\sqrt{\dfrac{l}{g}}\).

Find \(T\) when \(l = 0.8\) and \(g = 9.8\).

Q4 · analysis[2 marks]

Sam says that \(2x^{2}\) and \((2x)^{2}\) are always equal. Use \(x = 3\) to show that Sam is wrong.

Q5 · calculation[2 marks]

Use the formula \(F = \dfrac{9C}{5} + 32\) to find \(F\) when \(C = -15\).

Q6 · analysis[4 marks]

A taxi charges $3.50 plus $1.20 for each kilometre travelled.

(a) Write a formula for the cost, \(C\) dollars, of a journey of \(d\) kilometres.

(b) Find the cost of a 12 km journey.

(c) A journey costs $11.30. How long was it?

Answer key and marking notes
Q1 · 2 marks
  • (a) \(y - 7\)
  • (b) \(\dfrac{x}{4} + 3\)
Q2 · 3 marks
  • (a) \(5 - (-3) = 8\)
  • (b) \(b^{2} = 9\), so \(5 \times 9 = 45\)
  • (c) \(\dfrac{5 + (-3)}{8} = \dfrac{2}{8} = \dfrac{1}{4}\)
Q3 · 2 marks
  • \(\dfrac{0.8}{9.8} = 0.08163...\), and \(\sqrt{0.08163...} = 0.2857...\)
  • \(T = 2\pi \times 0.2857... = 1.795...\), so \(T = 1.80\) s (3 s.f.)
Q4 · 2 marks
  • \(2x^{2} = 2 \times 9 = 18\)
  • \((2x)^{2} = 6^{2} = 36\). \(18 \ne 36\), so Sam is wrong.
Q5 · 2 marks
  • \(\dfrac{9 \times (-15)}{5} = -27\)
  • \(F = -27 + 32 = 5\)
Q6 · 4 marks
  • (a) \(C = 3.5 + 1.2d\)
  • (b) \(C = 3.5 + 1.2 \times 12 = 3.5 + 14.4 = 17.9\), so $17.90
  • (c) \(3.5 + 1.2d = 11.3\), so \(1.2d = 7.8\)
  • \(d = 7.8 \div 1.2 = 6.5\) km
Quiz

6 multiple-choice questions on this lesson

From the topic question bank. Assign them in the app for a marked score in your gradebook, or run the topic as a class game.

Q11 mark

Which expression means 'subtract 4 from a number \(n\), then multiply the result by 5'?

  • A\(5(n - 4)\)
  • B\(5n - 4\)
  • C\(4 - 5n\)
  • D\(5(4 - n)\)
Q21 mark

Find the value of \(5a - 2b\) when \(a = -2\) and \(b = -3\).

  • A\(-4\)
  • B\(-16\)
  • C\(4\)
  • D\(16\)
Q31 mark

Find the value of \(4x^{2}\) when \(x = -3\).

  • A\(36\)
  • B\(144\)
  • C\(-36\)
  • D\(-24\)
Q41 mark

Use the formula \(v = u + at\) to find \(v\) when \(u = 12\), \(a = -3\) and \(t = 5\).

  • A\(-3\)
  • B\(27\)
  • C\(45\)
  • D\(3\)
Q51 mark

Ravi is \(y\) years old. His father's age is 4 less than three times Ravi's age. Which expression gives the sum of their ages in 5 years' time?

  • A\(4y + 6\)
  • B\(4y + 1\)
  • C\(4y - 4\)
  • D\(3y + 6\)
Q61 mark

Find the value of \(\dfrac{a^{2} - 3b}{a - b}\) when \(a = -4\) and \(b = 2\).

  • A\(-\dfrac{5}{3}\)
  • B\(\dfrac{11}{3}\)
  • C\(-5\)
  • D\(\dfrac{5}{3}\)
Quiz key
Q1: A

Subtracting 4 from \(n\) gives \(n - 4\). Multiplying the whole of that by 5 needs a bracket: \(5(n - 4)\). \(5n - 4\) multiplies first and subtracts second, which is the wrong order. \(5(4 - n)\) subtracts \(n\) from 4 instead of 4 from \(n\).

Q2: A

\(5(-2) - 2(-3) = -10 - (-6) = -10 + 6 = -4\). The answer \(-16\) comes from treating \(-2 \times -3\) as \(-6\): minus times minus is plus, so \(-2b\) is \(+6\).

Q3: A

\(x^{2} = (-3)^{2} = 9\), so \(4x^{2} = 4 \times 9 = 36\). 144 is \((4x)^{2} = (-12)^{2}\): the 4 is not inside the square. \(-36\) comes from typing \(-3^{2}\) without brackets, which a calculator reads as \(-9\). \(-24\) doubles instead of squares.

Q4: A

\(at = (-3)(5) = -15\), so \(v = 12 + (-15) = -3\). 45 comes from \((u + a)t = 9 \times 5\), adding before multiplying. 27 ignores the negative sign of \(a\).

Q5: A

Father now: \(3y - 4\). In 5 years: Ravi \(y + 5\), father \(3y - 4 + 5 = 3y + 1\). Sum: \(y + 5 + 3y + 1 = 4y + 6\). \(4y + 1\) adds the 5 years only once, but both people age. \(4y - 4\) is the sum of their ages now.

Q6: A

Top: \((-4)^{2} - 3(2) = 16 - 6 = 10\). Bottom: \(-4 - 2 = -6\). So the value is \(\dfrac{10}{-6} = -\dfrac{5}{3}\). \(\dfrac{11}{3}\) comes from \(-4^{2} = -16\) without brackets, giving \(\dfrac{-22}{-6}\). \(-5\) uses \(a + b = -2\) on the bottom.

Lab and demo

What to project

The student lesson embeds these tabs. Open them full screen on the projector; every slider has a drag handle on the stage.

Slides

Slides for this lesson

A projectable deck for every pack is on the way. Until then, present the student lesson full screen: its sections, figure and lab tabs follow the same order as the plan above.

Also for this topic

Everything else you can use

Original work by the TheLucidSTEM team. The worksheet items are written in the style of the papers; no past paper question is reproduced.