Teachers' Portal  /  IGCSE Maths 0580  /  Algebra and graphs  /  Forming and solving linear equations
Lesson pack · IGCSE Maths 0580 · 2.5 · IGCSE

Forming and solving linear equations

Keep the scales level. An equation is a balance: do the same to both sides and it stays true.

Student lesson Lab, full screen
At a glance

The shape of the lesson

Topic
Algebra and graphs
Syllabus reference
Cambridge IGCSE Mathematics 0580, 2.5
Level
IGCSE
Duration
45 minutes, lab-led; stretches to a 60 minute block (see the contingency notes)
Position in topic
Lesson 6 of 22 in Algebra and graphs; follows Indices II: algebraic and fractional indices; leads into Changing the subject of a formula
Central model
Whatever you do to one side of an equation, do to the other.
Cooperative structure
Assessment
Stage 1 check and the exam-style plenary from the student lesson, plus the worksheet as the exit task
Learning objectives

By the end of the lesson, learners can

Section by section
  • Solving on a balance: In the lab pick an equation and press Next step one move at a time.
  • Forming an equation: Choose a letter for the unknown, write each quantity in terms of it, then use a fact you know (angles in a triangle add to 180°, a perimeter, a total) to make an equation.
  • Fractional equations (Extended): Clear the fractions first.
Key points to leave on the board
  • Fractions (Extended): multiply every term by the common denominator first.
  • Brackets: expand, watching the sign of the number outside.
  • Collect: unknowns on the side where they stay positive, numbers on the other.
  • Divide: by the number in front of the unknown.
  • Check: substitute into the original equation; answer what was asked.
The core visual model

One picture every idea returns to

Whatever you do to one side of an equation, do to the other. Expand brackets, collect the unknown on one side and the numbers on the other, then divide. Check by substituting your answer back into the original equation.

Lesson sequence

Forty-five minutes, phase by phase

TimePhaseWhat happens in the roomGrouping
0 to 5 minHook: predictOpen with the question in the title, Keep the scales level.. An equation is a balance: do the same to both sides and it stays true.Whole class, then pairs
5 to 13 minTeach and check: Solving on a balanceIn the lab pick an equation and press Next step one move at a time. Project tab 1 of the lab (Equations lab, linear equations) and let a student drive it while the class predicts. Model the worked example Two steps on the board, one line at a time. Your turn: Solve \(8 - 3(x - 2) = 2(x + 4)\).Whole class, then pairs
13 to 21 minTeach and check: Forming an equationChoose a letter for the unknown, write each quantity in terms of it, then use a fact you know (angles in a triangle add to 180°, a perimeter, a total) to make an equation. Model the worked example Angles in a triangle on the board, one line at a time. Your turn: The sum of three consecutive whole numbers is 87. Find the numbers.Pairs
21 to 30 minTeach and check: Fractional equations (Extended)Clear the fractions first. Model the worked example Numerical denominators (Extended) on the board, one line at a time. Your turn: (Extended) Solve \(\dfrac{2x + 1}{x} = 4\).Rally Coach
30 to 36 minCheckThe four Stage 1 questions from the student lesson, answered on mini whiteboards or by show of fingers. Re-teach the one most get wrong.Individual, then whole class
36 to 43 minPlenaryThe exam-style questions from Stage 2, one at a time: thirty seconds alone, then a random call. The feedback lines in the key give the examiner's wording.Individual, random call
43 to 45 minExit and homeworkSet the worksheet below (6 questions, 20 marks). Learners self-assess against the objectives before they leave.Individual
Timing and contingency

Protect the parts that carry the learning

The sequence carries about fifty minutes of material, so the lab is driven by one student while the class predicts rather than explored freely. Times are a guide.

Protected: the check at 30 minutes. It is the only individual read on whether the key idea landed, and it is not cut.

Cut first if the build overruns: the last check in Fractional equations (Extended), never the check or the plenary.

In a 60 minute block: run worksheet questions 1 to 3 in class as a Rally Coach set and model both the hardest worked example and its check live.

Running the cooperative task

Rally Coach

Pairs share one worksheet. One partner solves the first question aloud while the other coaches, checking each line and offering a prompt rather than the answer; they swap roles for the next question.

The full structure, with its variations and the other twelve, is on the cooperative-learning page.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
In \(8 - 3(x - 2)\), the \(-3\) multiplies the \(-2\) as well: \(-3 \times (-2) = +6\).Writing \(8 - 3x - 6\) is the most common slip on this type.
Finding \(x\) is often not the end.Read the question again: it may ask for an angle, a length or an age built from \(x\).
Multiplying only the fractions by 6 and forgetting the 1 on the right gives \(7x + 4 = 1\).Every term, on both sides, must be multiplied.
Worksheet

Forming and solving linear equations: worksheet

6 questions, 20 marks. Written in the style of the papers; no past paper question is reproduced.

NameClassDate
Q1 · recall[2 marks]

Solve (a) \(7x - 3 = 25\) (b) \(\dfrac{x}{5} + 6 = 2\).

Q2 · calculation[3 marks]

Solve \(3(2x - 5) = 4x + 9\).

Q3 · calculation[3 marks]

Solve \(8 - 3(x - 2) = 2(x + 4)\).

Q4 · analysis[4 marks]

A rectangle has width \(w\) cm. Its length is 3 cm more than twice its width. The perimeter is 42 cm.

(a) Write an equation in \(w\). (b) Solve it and find the area of the rectangle.

Q5 · calculation[3 marks]

(Extended) Solve \(\dfrac{5}{x + 1} = \dfrac{2}{x - 2}\).

Q6 · analysis[5 marks]

Phone plan A costs $12 per month plus $0.05 per minute of calls. Plan B costs $20 per month plus $0.03 per minute.

(a) For \(m\) minutes of calls, write an equation for when the two plans cost the same.

(b) Solve your equation.

(c) Hana uses 500 minutes a month. Which plan is cheaper, and by how much?

Answer key and marking notes
Q1 · 2 marks
  • (a) \(7x = 28\), \(x = 4\)
  • (b) \(\dfrac{x}{5} = -4\), \(x = -20\)
Q2 · 3 marks
  • \(6x - 15 = 4x + 9\)
  • \(2x = 24\)
  • \(x = 12\)
Q3 · 3 marks
  • \(8 - 3x + 6 = 2x + 8\)
  • \(14 - 3x = 2x + 8\), so \(6 = 5x\)
  • \(x = 1.2\)
Q4 · 4 marks
  • (a) \(2(w + 2w + 3) = 42\)
  • (b) \(6w + 6 = 42\), \(6w = 36\), \(w = 6\)
  • Length \(= 2(6) + 3 = 15\) cm
  • Area \(= 6 \times 15 = 90\) cm2
Q5 · 3 marks
  • \(5(x - 2) = 2(x + 1)\)
  • \(5x - 10 = 2x + 2\), so \(3x = 12\)
  • \(x = 4\)
Q6 · 5 marks
  • (a) \(12 + 0.05m = 20 + 0.03m\)
  • (b) \(0.02m = 8\), so \(m = 400\) minutes
  • (c) A: \(12 + 0.05 \times 500 = \$37\). B: \(20 + 0.03 \times 500 = \$35\)
  • Plan B is cheaper by $2.
Quiz

6 multiple-choice questions on this lesson

From the topic question bank. Assign them in the app for a marked score in your gradebook, or run the topic as a class game.

Q11 mark

Solve \(7x - 4 = 3x + 10\).

  • A\(x = 3.5\)
  • B\(x = 1.5\)
  • C\(x = 1.4\)
  • D\(x = 14\)
Q21 mark

Solve \(3(2x + 5) = 4(x - 1)\).

  • A\(x = -9.5\)
  • B\(x = 9.5\)
  • C\(x = -4.5\)
  • D\(x = -8\)
Q31 mark

The angles of a quadrilateral are \(x\)°, \((2x + 10)\)°, \((3x - 20)\)° and \((2x + 50)\)°. Find the size of the largest angle.

  • A130°
  • B40°
  • C100°
  • D85°
Q41 mark

I think of a number. Multiplying it by 4 and adding 9 gives the same answer as multiplying it by 7 and subtracting 6. What is the number?

  • A5
  • B1
  • C\(-5\)
  • D15
Q51 mark

Solve \(\dfrac{x - 3}{4} - \dfrac{x + 1}{6} = 1\).

  • A\(x = 23\)
  • B\(x = 19\)
  • C\(x = 12\)
  • D\(x = 11.5\)
Q61 mark

Solve \(\dfrac{3}{x - 2} = \dfrac{5}{x + 4}\).

  • A\(x = 11\)
  • B\(x = -13\)
  • C\(x = 3\)
  • D\(x = -11\)
Quiz key
Q1: A

\(7x - 3x = 10 + 4\), so \(4x = 14\) and \(x = 3.5\). Check: \(7(3.5) - 4 = 20.5\) and \(3(3.5) + 10 = 20.5\). \(x = 1.5\) moves the \(-4\) across without changing its sign (\(4x = 6\)). \(x = 1.4\) adds the \(x\) terms to get \(10x = 14\).

Q2: A

\(6x + 15 = 4x - 4\), so \(2x = -19\) and \(x = -9.5\). \(x = -4.5\) expands \(3(2x + 5)\) as \(6x + 5\). \(x = -8\) expands \(4(x - 1)\) as \(4x - 1\). \(x = 9.5\) loses the minus sign of \(-19\).

Q3: A

\(x + 2x + 10 + 3x - 20 + 2x + 50 = 360\), so \(8x + 40 = 360\), \(8x = 320\), \(x = 40\). The angles are 40°, 90°, 100° and 130°, so the largest is 130°. 40° is \(x\), not the largest angle. 85° comes from using 180°, the angle sum of a triangle.

Q4: A

\(4n + 9 = 7n - 6\). Subtract \(4n\): \(9 = 3n - 6\). Add 6: \(15 = 3n\), so \(n = 5\). Check: \(4(5) + 9 = 29\) and \(7(5) - 6 = 29\). 15 stops before dividing by 3; 1 comes from \(3n = 9 - 6\).

Q5: A

\(\times 12\): \(3(x - 3) - 2(x + 1) = 12\), so \(3x - 9 - 2x - 2 = 12\), \(x - 11 = 12\), \(x = 23\). \(x = 19\) writes \(-2(x + 1)\) as \(-2x + 2\). \(x = 12\) forgets to multiply the right-hand side by 12. \(x = 11.5\) uses 24 on the left but leaves the 1 unchanged.

Q6: A

\(3(x + 4) = 5(x - 2)\), so \(3x + 12 = 5x - 10\), \(22 = 2x\), \(x = 11\). Check: \(\dfrac{3}{9} = \dfrac{1}{3}\) and \(\dfrac{5}{15} = \dfrac{1}{3}\). \(x = -13\) multiplies each numerator by its own denominator. \(x = 3\) drops the brackets: \(3x + 4 = 5x - 2\).

Lab and demo

What to project

The student lesson embeds these tabs. Open them full screen on the projector; every slider has a drag handle on the stage.

Slides

Slides for this lesson

A projectable deck for every pack is on the way. Until then, present the student lesson full screen: its sections, figure and lab tabs follow the same order as the plan above.

Also for this topic

Everything else you can use

Original work by the TheLucidSTEM team. The worksheet items are written in the style of the papers; no past paper question is reproduced.
Previous lessonIndices II: algebraic and fractional indices