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Worksheet · IGCSE 0625 · 1.2 Motion · Extended

Terminal velocity: practice

Six original Extended questions on the forces on a falling object and its terminal velocity. Remember: at terminal velocity the air resistance equals the weight, so the resultant force is zero. Explain using forces, and give a unit with every value.

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Q12 marks

A skydiver falls through the air. State the two forces acting on the skydiver and the direction of each.

Q23 marks

Just after jumping, the skydiver accelerates at about 9.8 m/s², but the acceleration soon becomes smaller. Explain why, using the forces.

Q32 marks

Define terminal velocity in terms of the forces acting on the falling object.

Q43 marks

Sketch the speed-time graph for a skydiver from jumping until reaching terminal velocity. On your sketch, state what the gradient shows at the start and at terminal velocity.

Blank speed-time axes with faint gridlines, ready for a sketch.
Sketch your answer on axes like these
Q53 marks

The skydiver then opens a parachute. Explain, using the forces, what happens to the motion immediately afterwards and what happens in the end.

Q62 marks

A skydiver has a weight of 750 N. State the size of the air resistance acting on the skydiver at terminal velocity, and give a reason.

Total: 15 marks. Original work by the TheLucidSTEM team. Written in the style of the papers; no past paper question is reproduced.

Answer key · full worked solutionsclick to reveal
Q1. The two forces.

weight, acting downward; and air resistance (drag), acting upward.

Q2. Why the acceleration falls.

Just after jumping the speed is low, so the air resistance is small (almost zero) and the resultant force is nearly the full weight, giving the largest acceleration, about g.

As the skydiver speeds up the air resistance grows, so the resultant force (weight minus air resistance) becomes smaller, and the acceleration becomes smaller with it.

Q3. Terminal velocity, by forces.

the constant (maximum) velocity reached when the air resistance has grown until it equals the weight, so the resultant force is zero and there is no acceleration.

Q4. The speed-time graph.

a curve that rises steeply from the origin, becomes less steep, and levels off to a horizontal line. at the start the gradient is large: a = g, the largest acceleration. at terminal velocity the gradient is zero: a = 0, a constant velocity.

The terminal-velocity speed-time graph: steep from the origin, becoming less steep, levelling to a horizontal line.
Steep at the start, flat at terminal velocity
Q5. Opening the parachute.

the parachute greatly increases the air resistance, so it is now larger than the weight. the resultant force is upward, so the skydiver decelerates (slows down). as the speed falls the air resistance falls, until it again equals the weight; the skydiver then falls at a new, lower terminal velocity.

The full skydiver speed-time graph: rising to a terminal velocity, then a steep drop when the parachute opens, levelling to a new lower terminal velocity.
The full journey, with the parachute opening
Q6. Air resistance at terminal velocity.

750 N. at terminal velocity the resultant force is zero, so the air resistance must equal the weight.

Marking note: in Q2 and Q5 award for naming the forces, for the resultant, and for the effect on the acceleration or speed. In Q4 award for the correct curve shape and for both gradient statements.
Original work by the TheLucidSTEM team. Questions are written in the style of the papers; no past paper question is reproduced. Supplied in editable formats so you can adapt them freely.
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