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Worksheet · AS 9702 · 1.3 Physical quantities and units

Measurement uncertainties: practice

Random and systematic error, reading uncertainties, the combining rules and expressing a result. Show your working, give uncertainties to one significant figure, and match the value to the same decimal place.

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Name: ________________Class: __________Date: __________
Sums and differences add absolute uncertainties; products and quotients add percentage uncertainties; a power n multiplies the percentage uncertainty by n.
Section A · Recall
A13 marks

Explain the difference between a random error and a systematic error, and state how each can be reduced.

A22 marks

Explain the difference between precision and accuracy.

Section B · Reading uncertainties
B12 marks

A digital balance with a resolution of 0.01 g reads 24.56 g. State the absolute and percentage uncertainty.

B22 marks

An analogue ammeter with smallest divisions of 0.1 A reads 2.4 A. State the absolute and percentage uncertainty.

B33 marks

Five timings are 2.1, 2.3, 2.2, 2.0 and 2.4 s. Find the mean and estimate the uncertainty using half the range.

Section C · Combining uncertainties
C12 marks

x = 8.0 ± 0.2 cm and y = 5.0 ± 0.1 cm. Find z = x + y and its absolute uncertainty.

C23 marks

A current I = 2.0 ± 0.1 A passes through a resistor R = 10.0 ± 0.5 Ω. Find V = I R, its percentage uncertainty and its absolute uncertainty.

C32 marks

A pendulum gives g = 4 π2 l / T2. The length l has a 1 percent uncertainty and the period T has a 1 percent uncertainty. Find the percentage uncertainty in g.

C42 marks

A circle has radius r = 3.00 ± 0.05 cm. Find the percentage uncertainty in its area A = π r2.

Section D · Express the result
D13 marks

A density is found from ρ = m / V with m = 120.0 ± 0.5 g and V = 50.0 ± 1.0 cm3. Calculate ρ and state it as a value plus or minus an uncertainty to an appropriate number of significant figures.

Section E · Reasoning
E12 marks

Explain why averaging many readings reduces the random error but not a systematic error.

E22 marks

A learner always starts a stopwatch a moment after the event begins. State the type of error this produces and its effect on the readings.

Total: 28 marks. Original work by the TheLucidSTEM team. Written in the style of the papers; no past paper question is reproduced.

Answer key · full worked solutionsclick to reveal
A1. Random and systematic error.

a random error scatters readings either side of the true value and is reduced by repeating and averaging. A systematic error shifts all readings the same way and is reduced by zeroing or calibrating the instrument and improving technique; repeating does not reduce it.

A2. Precision and accuracy.

precision is how close repeated readings are to one another; accuracy is how close a reading is to the true value.

B1. Digital balance.

absolute uncertainty = 0.01 g (the resolution); percentage = (0.01 / 24.56) × 100 = 0.04 percent.

B2. Analogue ammeter.

absolute uncertainty = half the smallest division = 0.05 A; percentage = (0.05 / 2.4) × 100 = 2 percent.

B3. Five timings.

mean = (2.1 + 2.3 + 2.2 + 2.0 + 2.4) / 5 = 2.2 s; range = 2.4 − 2.0 = 0.4 s; uncertainty = half the range = 0.2 s, so 2.2 ± 0.2 s.

C1. z = x + y.

z = 8.0 + 5.0 = 13.0 cm; Δz = 0.2 + 0.1 = 0.3 cm, so z = 13.0 ± 0.3 cm.

C2. V = I R.

percentage uncertainties: I gives 5 percent, R gives 5 percent; total = 10 percent. V = 2.0 × 10.0 = 20 V; absolute uncertainty = 10 percent of 20 = 2 V, so V = 20 ± 2 V.

C3. g = 4 π2 l / T2.

g depends on T2, so its percentage uncertainty = 1 percent (from l) + 2 × 1 percent (from T) = 3 percent.

C4. A = π r2.

A depends on r2, so percentage uncertainty = 2 × (0.05 / 3.00) × 100 = 2 × 1.67 = 3.3 percent.

D1. Express ρ.

ρ = 120.0 / 50.0 = 2.40 g cm−3. Percentage uncertainties: m gives (0.5 / 120.0) × 100 = 0.4 percent; V gives (1.0 / 50.0) × 100 = 2.0 percent; total = 2.4 percent. Absolute uncertainty = 2.4 percent of 2.40 = 0.06 g cm−3, so ρ = 2.40 ± 0.06 g cm−3.

E1. Why averaging helps random only.

random errors are equally likely to be above or below the true value, so averaging many readings cancels much of the scatter. A systematic error shifts every reading the same way, so the shift remains in the average and is not reduced by averaging.

E2. Late stopwatch start.

a systematic error. Every recorded time is shorter than the true time by roughly the same amount, so all readings are offset in the same direction.

Marking note: quote uncertainties to one significant figure and match the value to the same decimal place. In Section C, accept the percentage or the absolute form provided the method is shown.
Original work by the TheLucidSTEM team. Questions are written in the style of the papers; no past paper question is reproduced. Supplied in editable formats so you can adapt them freely.
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