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Lesson plan · AS 9702 · 6.1 · Deformation of solids

Stress, strain and the Young modulus

An AS lesson that separates stiffness from strength: define stress and strain, read a stress-strain graph, and find the Young modulus as the gradient of its straight region, the same for every sample of the material.

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At a glance

The shape of the lesson

Topic
Stress, strain and the Young modulus (subtopic 6.1)
Syllabus reference
Cambridge International AS & A Level Physics 9702, 6.1 (Topic 6: Deformation of solids)
Level
AS (first year)
Duration
60 minutes (single period)
Prior knowledge
Hooke's law (F = k x), force-extension graphs, the limit of proportionality
Central visual model
The stress-strain graph: gradient of the straight region = the Young modulus
Simulation
Stretching a Wire (Deformation), loading a wire and reading the stress-strain line
Cooperative structure
Numbered Heads Together (full facilitation guide in the activity materials)
21st century skills
Collaboration, Critical Thinking
Assessment
An exit ticket (one calculation, one explanation), plus random call after the discussion
Learning objectives

By the end of the lesson, learners can

AS (all learners)
  • define tensile stress and tensile strain, and state the unit of each
  • define the Young modulus and use E = stress ÷ strain
  • calculate tensile stress, tensile strain and the Young modulus for a wire
  • interpret a stress-strain graph, including the limit of proportionality and the elastic and plastic regions
  • describe an experiment to determine the Young modulus of a metal in the form of a wire
  • explain that the Young modulus is a property of the material, not of the dimensions of the sample

Key vocabulary

tensile stress, tensile strain, the Young modulus, pascal, limit of proportionality, elastic limit, elastic and plastic deformation, stiffness, strength, cross-sectional area. Each term is introduced as it is first needed.

The core ideas

Three definitions, one material property

Stress is the load shared over the cross-section; strain is the fractional stretch; the Young modulus is the ratio of the two. Setting them out together makes the units fall into place: stress is in pascals, strain is a pure ratio, so the Young modulus is also in pascals.

Tensile stress equals force over area in pascals; tensile strain equals extension over original length with no unit; the Young modulus equals stress over strain, equivalently F L over A x, in pascals.
The defining equations, and how the units follow
QuantityEquationUnit
Tensile stress, σσ = F / APa (N m−2)
Tensile strain, εε = x / Lnone (a ratio)
Young modulus, EE = σ / ε = F L / (A x)Pa (often GPa)
Area of wire, AA = π d2 / 4m2
Elastic strain energyEp = ½ F x = ½ k x2J

Read the graph, and keep the material separate from the specimen

The Young modulus is the gradient of the straight region of the stress-strain graph, up to the limit of proportionality. Beyond the elastic limit the deformation is plastic and the wire no longer returns to its original length. The key distinction to protect: a force-extension graph belongs to one specimen and depends on its length and thickness, while a stress-strain graph belongs to the material and is the same for every sample.

A stress-strain graph: a straight line from the origin to the limit of proportionality P, where the gradient equals the Young modulus, then a curve into the plastic region, with the elastic limit just beyond P.
The gradient of the straight region is the Young modulus
Force-extension graphs differ from specimen to specimen, but every specimen of the same material falls on one stress-strain line whose gradient is the Young modulus.
Specimen (force-extension) versus material (stress-strain)
Lesson sequence

Sixty minutes, phase by phase

TimePhaseWhat happens in the roomResources
0 to 5 minStarterThree true-or-false statements on stiffness, strength and the units of strain. Learners decide individually, then show hands; hold the disagreements for later.Slides 1 to 2
5 to 10 minRecapRecall Hooke's law and the force-extension graph; define the limit of proportionality. Learners sketch a force-extension line and label it.Slide 3
10 to 25 minTeachDefine stress, strain and the Young modulus; build the stress-strain graph; contrast it with the force-extension graph for one specimen.Slides 4 to 8, fig-stress-strain
25 to 30 minModelWork the steel-wire example on the board, setting out method and units; learners predict each next step.Slide 9, worked example below
30 to 48 minActivityNumbered Heads Together on the team problem set; groups solve until every member can explain, then a random number is called.Numbered Heads activity sheet
48 to 55 minExperimentWalk through the Young modulus of a wire experiment and its main uncertainty: what to plot, and why the diameter dominates the error.Slides 10 to 12, fig-wire-experiment
55 to 60 minPlenaryExit ticket: one calculation and one explanation, completed individually and handed in.Exit ticket on the final slide
Worked example for the board

A steel wire, step by step

A steel wire of original length L = 2.00 m and diameter d = 0.50 mm stretches by x = 2.0 mm when a load F = 40 N is applied. Find the stress, the strain and the Young modulus.

Area: A = π d2 / 4 = π (0.50 × 10−3)2 / 4 = 1.96 × 10−7 m2
Stress: σ = F / A = 40 / (1.96 × 10−7) = 2.04 × 108 Pa (about 204 MPa)
Strain: ε = x / L = (2.0 × 10−3) / 2.00 = 1.0 × 10−3
Young modulus: E = σ / ε = (2.04 × 108) / (1.0 × 10−3) = 2.0 × 1011 Pa (about 200 GPa)
The required practical

The Young modulus of a wire

A long thin metal wire is clamped at one end and run horizontally over a pulley at the edge of the bench (or hung vertically), with a reference marker on the wire over a rule, and slotted masses providing the load. The aim is to load the wire in steps, record the extension, and find E from the gradient.

A wire clamped at one end runs horizontally over a pulley to a hanger of slotted masses; a marker on the wire reads the extension on a rule, and the diameter is measured with a micrometer.
Load in steps, read the extension at the marker, plot stress against strain

Method

Precautions and uncertainty

Running the cooperative task

Numbered Heads Together

Learners work in groups of four and number off 1 to 4. The teacher poses one problem from the set; the group works until every member can explain the answer, not just write it. A random number is then called, and that learner answers for the group with no further help. Because the responder is chosen at random after discussion, no learner can hide and no single voice can dominate. A full step-by-step facilitation guide, with the team problem set and the teacher answer key, is provided as the activity in this bundle, so it can be run faithfully, including by a cover teacher.

Why it suits this lesson. The hard part of 6.1 is reasoning through multi-step calculations and the stiffness-versus-strength distinction. The structure forces that talk and keeps every learner accountable for the method and the units, not just the final value.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
"A thicker or shorter wire has a larger Young modulus."The Young modulus is a material constant; it does not depend on the sample's dimensions. A thicker wire is stiffer as a specimen, but the ratio stress ÷ strain is unchanged.
Confusing strength with stiffness.A high Young modulus means stiff (hard to stretch), not strong (high breaking stress). Keep the two graphs and the two words apart.
Treating the stress-strain graph as a force-extension graph.The stress-strain graph is a property of the material; the force-extension graph is a property of that one specimen. Use fig-specimen-vs-material to separate them.
Giving strain a unit.Strain is a ratio of two lengths, so it has no unit. Check this on every answer.
Using diameter where radius is needed, or forgetting A depends on d2.A = π d2 / 4 (equivalently π r2). Doubling d quarters the stress for a given load, so the extension changes a lot.
Differentiation and assessment

Support, challenge and the checks

Assessment is formative. Exit ticket question 1 (calculation): a wire of area 2.0 × 10−7 m2 and length 1.5 m extends 0.90 mm under a 30 N load; find the Young modulus. Exit ticket question 2 (explanation): in one sentence, explain why two wires of the same metal but different thickness have the same Young modulus. Random call after Numbered Heads Together gives a quick read on individual understanding.

Equipment and resources

Original work by the TheLucidSTEM team. Items are written in the style of the papers; no past paper question is reproduced. Supplied in editable formats so you can adapt them freely.
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