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Worksheet · IGCSE 0625 · 1.2 Motion · Core

Distance-time graphs: practice

Six original questions on reading and sketching distance-time graphs. Remember: the gradient is the speed, and a horizontal line is stationary.

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Name: ________________Class: __________Date: __________
Q12 marks

State what each of these shows on a distance-time graph: (a) a horizontal line; (b) a straight line that slopes upwards.

Q24 marks

The distance-time graph below shows a short journey.

A distance-time graph rising from 0 to 40 metres in 20 seconds, level until 35 seconds, then falling back to 0 at 50 seconds.
Distance-time graph for Q2

(a) Describe the motion between 20 s and 35 s.   (b) Calculate the speed during the first 20 s.   (c) Is the object faster or slower on the way back than on the way out? Give a reason.

Q32 marks

A student says, "a horizontal line on a distance-time graph means the object moves at constant speed." Explain why this is wrong, and state what a horizontal line really means.

Q43 marks

Sketch a distance-time graph for this journey: stationary for 10 s, then a constant speed away from the start for 20 s. Label the axes.

Blank distance-time axes with faint gridlines, ready for a sketch.
Sketch your answer on axes like these
Q52 marks

On a distance-time graph an object moves from 10 m to 70 m between 5 s and 25 s. Calculate its speed.

Q62 marks

Describe the motion shown by (a) a curve that gets steeper, and (b) a curve that gets less steep.

Total: 15 marks. Original work by the TheLucidSTEM team. Written in the style of the papers; no past paper question is reproduced.

Answer key · full worked solutionsclick to reveal
Q1. Reading the lines.

(a) a horizontal line means the object is stationary (the distance is not changing).

(b) a straight sloped line means a constant speed.

Q2. Reading the graph.

(a) between 20 s and 35 s the line is horizontal, so the object is stationary.

(b) speed = gradient = 40 ÷ 20 = 2 m/s.

(c) faster on the way back: the return covers 40 m in 15 s (about 2.7 m/s), a steeper line than the outward 40 m in 20 s.

Q3. The horizontal-line trap.

a horizontal line is not constant speed. The distance is not changing, so the object is stationary. Constant speed is shown by a straight line that slopes upwards.

Q4. Sketch.

expected shape: a horizontal line for the first 10 s (stationary), then a straight line sloping upwards for the next 20 s (constant speed). Axes labelled distance / m against time / s.

Q5. Speed from the graph.

speed = gradient = (70 − 10) ÷ (25 − 5) = 60 ÷ 20 = 3 m/s.

Q6. Curved lines.

(a) a curve that gets steeper shows the object speeding up.

(b) a curve that gets less steep shows the object slowing down.

Marking note: in Q2(b) and Q5, the gradient must be read with a large triangle and the unit m/s given. In Q4, award for the horizontal section, the sloped section, and labelled axes.
Original work by the TheLucidSTEM team. Questions are written in the style of the papers; no past paper question is reproduced. Supplied in editable formats so you can adapt them freely.
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