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Lesson pack · IGCSE Physics 0625 · 1.5.2 · Core

Moments

The turning effect of a force. A small child can balance a heavier one on a seesaw, simply by sitting further out.

Student lesson Lab, full screen
At a glance

The shape of the lesson

Topic
Forces
Syllabus reference
Cambridge IGCSE Physics 0625, 1.5.2
Level
Core
Duration
45 minutes, lab-led; stretches to a 60 minute block (see the contingency notes)
Position in topic
Lesson 7 of 8 in Forces; follows Friction and drag; leads into Centre of gravity
Central model
The moment of a force is the force multiplied by the perpendicular distance from the pivot: moment = F × d, in newton metres (N m).
Cooperative structure
Assessment
Stage 1 check and the exam-style plenary from the student lesson, plus the worksheet as the exit task
Learning objectives

By the end of the lesson, learners can

Section by section
  • Balance the seesaw: Slide the weights along the beam and watch the moments.
  • Balancing the moments.
Key points to leave on the board
  • Principle of moments: clockwise moments = anticlockwise moments about the pivot.
  • Equilibrium: no resultant force AND no resultant moment, both at once.
  • Distance: always the perpendicular distance from the pivot to the line of action.
The core visual model

One picture every idea returns to

The moment of a force is the force multiplied by the perpendicular distance from the pivot: moment = F × d, in newton metres (N m). For an object in equilibrium, the principle of moments states that the total clockwise moment equals the total anticlockwise moment about any pivot.

Lesson sequence

Forty-five minutes, phase by phase

TimePhaseWhat happens in the roomGrouping
0 to 5 minHook: predictOpen with the question in the title, The turning effect of a force.. A small child can balance a heavier one on a seesaw, simply by sitting further out.Whole class, then pairs
5 to 17 minTeach and check: Balance the seesawSlide the weights along the beam and watch the moments. Project tab 5 of the lab (Moments) and let a student drive it while the class predicts.Whole class, then pairs
17 to 30 minTeach and check: Balancing the momentsBalancing the moments. Model the worked example Worked example on the board, one line at a time.Connect-Extend-Challenge
30 to 36 minCheckThe four Stage 1 questions from the student lesson, answered on mini whiteboards or by show of fingers. Re-teach the one most get wrong.Individual, then whole class
36 to 43 minPlenaryThe exam-style questions from Stage 2, one at a time: thirty seconds alone, then a random call. The feedback lines in the key give the examiner's wording.Individual, random call
43 to 45 minExit and homeworkSet the worksheet below (6 questions, 13 marks). Learners self-assess against the objectives before they leave.Individual
Timing and contingency

Protect the parts that carry the learning

The sequence carries about fifty minutes of material, so the lab is driven by one student while the class predicts rather than explored freely. Times are a guide.

Protected: the check at 30 minutes. It is the only individual read on whether the key idea landed, and it is not cut.

Cut first if the build overruns: the last check in Balancing the moments, never the check or the plenary.

In a 60 minute block: run worksheet questions 1 to 3 in class as a Rally Coach set and model both the hardest worked example and its check live.

Running the cooperative task

Connect-Extend-Challenge

After the new idea, each student writes three lines: how it connects to what they knew, how it extends their thinking, and what still challenges them. Pairs compare, then the challenges become the plenary.

The full structure, with its variations and the other twelve, is on the cooperative-learning page.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
Two traps in one topic.First, a moment uses the perpendicular distance from the pivot to the line of action of the force, not the length of the beam or a slanted distance. Second, balancing moments alone is not full equilibrium. An object is in equilibrium only when there is both no resultant force and no resultant moment. An answer that mentions only one of these is incomplete.
Worksheet

Moments: worksheet

6 questions, 13 marks. Written in the style of the papers; no past paper question is reproduced.

NameClassDate
Q1[2 marks]

Define the moment of a force and state its unit.

Q2 · calc[2 marks]

A force of 20 N acts at a perpendicular distance of 0.30 m from a pivot. Calculate the moment.

Q3 · analysis[2 marks]

State the principle of moments.

Q4 · calc[3 marks]

A uniform beam is pivoted at its centre. A 12 N weight hangs 0.50 m to the left of the pivot. A second weight hangs 0.30 m to the right and the beam balances. Calculate the second weight.

Q5 · analysis[2 marks]

State the two conditions that must both be satisfied for an object to be in equilibrium.

Q6 · analysis[2 marks]

When calculating a moment, a student measures the distance along a beam that is tilted, rather than the horizontal distance from the pivot. Explain why this gives the wrong moment.

Answer key and marking notes
Q1 · 2 marks
  • The moment of a force = force × perpendicular distance from the pivot. ✓
  • Unit: newton metre (N m). ✓
Q2 · 2 marks
  • moment = F × d = 20 × 0.30

    6.0 N m

Q3 · 2 marks

For an object in equilibrium, the total clockwise moment about a pivot equals the total anticlockwise moment about the same pivot. ✓✓

Q4 · 3 marks
  • Balance. clockwise = anticlockwise

    W × 0.30 = 12 × 0.50 W = 6.0 ÷ 0.30

    W = 20 N

Q5 · 2 marks
  • There is no resultant force on it. ✓
  • There is no resultant moment (clockwise moments = anticlockwise moments). ✓
Q6 · 2 marks
  • A moment uses the perpendicular distance from the pivot to the line of action of the force. ✓
  • The slanted distance along the beam is longer than the perpendicular distance, so the calculated moment is too large. ✓
Quiz

2 multiple-choice questions on this lesson

From the topic question bank. Assign them in the app for a marked score in your gradebook, or run the topic as a class game.

Q11 mark

A spanner turns a nut. A force of 25 N is applied at a perpendicular distance of 0.20 m from the nut. What is the moment of the force about the nut?

25 N 0.20 m
  • A0.0080 N m
  • B5.0 N m
  • C12.5 N m
  • D125 N m
Q21 mark

A uniform beam is balanced on a central pivot. A 4.0 N weight sits 30 cm to the left of the pivot. At what distance to the right must a 6.0 N weight be placed to balance the beam?

4.0 N 6.0 N 30 cm d = ?
  • A12 cm
  • B20 cm
  • C45 cm
  • D80 cm
Quiz key
Q1: B

moment = 25 × 0.20 = 5.0 N m. Option D divides instead of multiplying; A inverts the calculation.

Q2: B

4.0 × 30 = 6.0 × d, so d = 120 ÷ 6 = 20 cm. The heavier weight sits closer to the pivot. Option C scales the wrong way (multiplying by 1.5 instead of dividing).

Lab and demo

What to project

The student lesson embeds these tabs. Open them full screen on the projector; every slider has a drag handle on the stage.

Slides

Slides for this lesson

A projectable deck for every pack is on the way. Until then, present the student lesson full screen: its sections, figure and lab tabs follow the same order as the plan above.

Also for this topic

Everything else you can use

Original work by the TheLucidSTEM team. The worksheet items are written in the style of the papers; no past paper question is reproduced.
Previous lessonFriction and drag