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Lesson pack · IGCSE Physics 0625 · 3.2.2 · Extended (Supplement)

Refractive index

Counting the slowdown. How much a material bends light can be captured in a single number.

Student lesson Lab, full screen
At a glance

The shape of the lesson

Topic
Light
Syllabus reference
Cambridge IGCSE Physics 0625, 3.2.2
Level
Extended (Supplement)
Duration
45 minutes, lab-led; stretches to a 60 minute block (see the contingency notes)
Position in topic
Lesson 4 of 8 in Light; follows Total internal reflection; leads into Optical fibres
Central model
The refractive index n equals sin(i) divided by sin(r), where i is the angle in air and r the angle in the medium.
Cooperative structure
Assessment
Stage 1 check and the exam-style plenary from the student lesson, plus the worksheet as the exit task
Learning objectives

By the end of the lesson, learners can

Section by section
  • Measure the bending: Change the angle of incidence and read off the angle of refraction to see the refractive index that links them.
  • One number, three meanings: The refractive index can be found from angles, from the critical angle, or from speeds.
Key points to leave on the board
  • Trapping. Light hits the core boundary above the critical angle, so it is totally internally reflected and stays in the core.
  • Drawing. The path is straight line segments meeting the boundary at sharp angles, never a curved or wavy line.
  • Uses. Telecommunications (high capacity, low loss) and medical endoscopes.
The core visual model

One picture every idea returns to

The refractive index n equals sin(i) divided by sin(r), where i is the angle in air and r the angle in the medium. It also equals the speed of light in vacuum divided by its speed in the medium, and it links to the critical angle by n = 1 / sin(c). A larger n bends light more.

Lesson sequence

Forty-five minutes, phase by phase

TimePhaseWhat happens in the roomGrouping
0 to 5 minHook: predictOpen with the question in the title, Counting the slowdown.. How much a material bends light can be captured in a single number.Whole class, then pairs
5 to 17 minTeach and check: Measure the bendingChange the angle of incidence and read off the angle of refraction to see the refractive index that links them. Project tab 3 of the lab (Refractive index) and let a student drive it while the class predicts.Whole class, then pairs
17 to 30 minTeach and check: One number, three meaningsThe refractive index can be found from angles, from the critical angle, or from speeds. Model the worked example Worked example on the board, one line at a time.Connect-Extend-Challenge
30 to 36 minCheckThe four Stage 1 questions from the student lesson, answered on mini whiteboards or by show of fingers. Re-teach the one most get wrong.Individual, then whole class
36 to 43 minPlenaryThe exam-style questions from Stage 2, one at a time: thirty seconds alone, then a random call. The feedback lines in the key give the examiner's wording.Individual, random call
43 to 45 minExit and homeworkSet the worksheet below (6 questions, 16 marks). Learners self-assess against the objectives before they leave.Individual
Timing and contingency

Protect the parts that carry the learning

The sequence carries about fifty minutes of material, so the lab is driven by one student while the class predicts rather than explored freely. Times are a guide.

Protected: the check at 30 minutes. It is the only individual read on whether the key idea landed, and it is not cut.

Cut first if the build overruns: the last check in One number, three meanings, never the check or the plenary.

In a 60 minute block: run worksheet questions 1 to 3 in class as a Rally Coach set and model both the hardest worked example and its check live.

Running the cooperative task

Connect-Extend-Challenge

After the new idea, each student writes three lines: how it connects to what they knew, how it extends their thinking, and what still challenges them. Pairs compare, then the challenges become the plenary.

The full structure, with its variations and the other twelve, is on the cooperative-learning page.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
In n = sin i / sin r, i is the angle in air (the less dense medium) and r the angle in the glass.For the critical-angle relation n = 1 / sin c, the critical angle c is measured inside the denser medium. Mixing up which angle is which is the usual error.
Worksheet

Refractive index: worksheet

6 questions, 16 marks. Written in the style of the papers; no past paper question is reproduced.

NameClassDate
Q1[2 marks]

Define what is meant by the refractive index of a material, and write down the equation that links it to the angles of incidence and refraction.

Q2 · analysis[3 marks]

A ray of light passes from air into a glass block. The angle of incidence is 50 degrees and the angle of refraction is 30 degrees. Calculate the refractive index of the glass.

Q3 · analysis[3 marks]

A transparent plastic has a refractive index of 1.4. Calculate its critical angle.

Q4[2 marks]

Light travels at 3.0 × 10⁸ m/s in a vacuum and at 2.0 × 10⁸ m/s in a certain glass. Calculate the refractive index of the glass.

Q5 · analysis[3 marks]

Two materials A and B have refractive indices of 1.33 and 1.52. (a) Which material bends light more? (b) Which has the smaller critical angle? Explain your answer to part (b).

Q6 · analysis[3 marks]

A ray going from air into a glass block has an angle of incidence of 40 degrees and an angle of refraction of 25 degrees. (a) Calculate the refractive index. (b) State what happens to the frequency of the light as it enters the glass.

Answer key and marking notes
Q1 · 2 marks
  • The refractive index is a measure of how much the material slows down and bends light ✓
  • n = sin i ÷ sin r, where i is the angle in air and r the angle in the material ✓
Q2 · 3 marks
  • n = sin i ÷ sin r = sin 50 ÷ sin 30 ✓
  • = 0.766 ÷ 0.500 ✓
  • n = 1.53, about 1.5 ✓
Q3 · 3 marks
  • sin c = 1 ÷ n = 1 ÷ 1.4 ✓
  • sin c = 0.714 ✓
  • c = 46 degrees (about 46 degrees) ✓
Q4 · 2 marks
  • n = speed in vacuum ÷ speed in the medium ✓
  • n = (3.0 × 10⁸) ÷ (2.0 × 10⁸) = 1.5 ✓
Q5 · 3 marks
  • (a) Material B bends light more, because a higher refractive index means more bending ✓
  • (b) Material B has the smaller critical angle ✓
  • because sin c = 1 ÷ n, so a larger n gives a smaller critical angle ✓
Q6 · 3 marks
  • (a) n = sin 40 ÷ sin 25 = 0.643 ÷ 0.423 ✓
  • n = 1.52, about 1.5 ✓
  • (b) The frequency stays the same ✓
Quiz

5 multiple-choice questions on this lesson

From the topic question bank. Assign them in the app for a marked score in your gradebook, or run the topic as a class game.

Q11 mark

A ray of light passes from air into glass. The angle of incidence is 50° and the angle of refraction is 30°. What is the refractive index of the glass?

i = 50° r = 30°
  • A0.65
  • B1.5
  • C1.7
  • D2.0
Q21 mark

Light travels from air into a glass block of refractive index 1.5 at an angle of incidence of 49°. What is the angle of refraction? (sin 49° = 0.75)

  • A30°
  • B33°
  • C42°
  • D73°
Q31 mark

How is the refractive index of a material defined for light entering it from air?

  • Asin(angle of incidence) ÷ sin(angle of refraction)
  • Bangle of incidence ÷ angle of refraction
  • Csin(angle of refraction) ÷ sin(angle of incidence)
  • Dthe speed of light in the material × the angle of incidence
Q41 mark

Light travels more slowly in material A (n = 1.5) than in material B (n = 1.3). Which statement is correct?

  • AMaterial A is optically denser and refracts light more.
  • BMaterial B is optically denser and refracts light more.
  • CBoth materials refract light by the same amount.
  • DNeither material refracts light.
Q51 mark

As light passes from air into a denser, transparent medium, what happens to its wavelength and frequency?

  • AThe wavelength decreases and the frequency stays the same.
  • BBoth decrease.
  • CThe wavelength increases and the frequency stays the same.
  • DThe frequency decreases and the wavelength stays the same.
Quiz key
Q1: B

n = sin 50° ÷ sin 30° = 0.766 ÷ 0.500 = 1.5. Option A inverts the ratio (sin r ÷ sin i); the value must be greater than 1 for glass.

Q2: A

sin r = sin i ÷ n = 0.75 ÷ 1.5 = 0.50, so r = 30°. Option D multiplies instead of dividing, bending the ray the wrong way.

Q3: A

Refractive index n = sin i ÷ sin r, using the sines of the angles measured from the normal. Option B uses the angles directly, which is incorrect, and C inverts the ratio.

Q4: A

A higher refractive index means the light slows more and bends more, so material A (n = 1.5) is optically denser and refracts light more strongly than material B.

Q5: A

The frequency is unchanged on entering the medium, but the speed falls, so from v = fλ the wavelength decreases. The frequency does not change (ruling out B and D).

Lab and demo

What to project

The student lesson embeds these tabs. Open them full screen on the projector; every slider has a drag handle on the stage.

Slides

Slides for this lesson

A projectable deck for every pack is on the way. Until then, present the student lesson full screen: its sections, figure and lab tabs follow the same order as the plan above.

Also for this topic

Everything else you can use

Original work by the TheLucidSTEM team. The worksheet items are written in the style of the papers; no past paper question is reproduced.
Previous lessonTotal internal reflection