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Lesson pack · IGCSE Physics 0625 · 1.6 · Extended (Supplement)

Impulse and force

Spread the change over more time. A china plate shatters on concrete but survives on a carpet, from the very same fall.

Student lesson Lab, full screen
At a glance

The shape of the lesson

Topic
Momentum (Extended only)
Syllabus reference
Cambridge IGCSE Physics 0625, 1.6
Level
Extended (Supplement)
Duration
45 minutes, lab-led; stretches to a 60 minute block (see the contingency notes)
Position in topic
Lesson 2 of 2 in Momentum (Extended only); follows Momentum and conservation
Central model
The resultant force equals the rate of change of momentum: F = Δp ÷ Δt = (mv − mu) ÷ t.
Cooperative structure
Assessment
Stage 1 check and the exam-style plenary from the student lesson, plus the worksheet as the exit task
Learning objectives

By the end of the lesson, learners can

Section by section
  • Stretch the time, soften the blow: Set the same change in momentum, then vary the time it takes.
  • Why time is the lever.
Key points to leave on the board
  • Resultant force: equals the rate of change of momentum.
  • Longer time: smaller force for the same change in momentum.
  • Rebounds: use signed velocities, so Δp is larger than for stopping alone.
The core visual model

One picture every idea returns to

The resultant force equals the rate of change of momentum: F = Δp ÷ Δt = (mv − mu) ÷ t. For a given change in momentum, a longer time produces a smaller force, and a shorter time a larger one.

Lesson sequence

Forty-five minutes, phase by phase

TimePhaseWhat happens in the roomGrouping
0 to 5 minHook: predictOpen with the question in the title, Spread the change over more time.. A china plate shatters on concrete but survives on a carpet, from the very same fall.Whole class, then pairs
5 to 17 minTeach and check: Stretch the time, soften the blowSet the same change in momentum, then vary the time it takes. Project tab 2 of the lab (Impulse and force) and let a student drive it while the class predicts.Whole class, then pairs
17 to 30 minTeach and check: Why time is the leverWhy time is the lever. Model the worked example Worked example on the board, one line at a time.Round Table
30 to 36 minCheckThe four Stage 1 questions from the student lesson, answered on mini whiteboards or by show of fingers. Re-teach the one most get wrong.Individual, then whole class
36 to 43 minPlenaryThe exam-style questions from Stage 2, one at a time: thirty seconds alone, then a random call. The feedback lines in the key give the examiner's wording.Individual, random call
43 to 45 minExit and homeworkSet the worksheet below (6 questions, 15 marks). Learners self-assess against the objectives before they leave.Individual
Timing and contingency

Protect the parts that carry the learning

The sequence carries about fifty minutes of material, so the lab is driven by one student while the class predicts rather than explored freely. Times are a guide.

Protected: the check at 30 minutes. It is the only individual read on whether the key idea landed, and it is not cut.

Cut first if the build overruns: the last check in Why time is the lever, never the check or the plenary.

In a 60 minute block: run worksheet questions 1 to 3 in class as a Rally Coach set and model both the hardest worked example and its check live.

Running the cooperative task

Round Table

One sheet travels round the team. Each student adds one line of working or one idea and passes it on, so the solution is built four hands at a time and every contribution is visible.

The full structure, with its variations and the other twelve, is on the cooperative-learning page.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
When a question asks why a safety feature reduces the force, the answer is the time.The change in momentum is set by the masses and speeds and cannot be altered. It is the longer time of the collision that lowers the force, since F = change in momentum divided by time.
Worksheet

Impulse and force: worksheet

6 questions, 15 marks. Written in the style of the papers; no past paper question is reproduced.

NameClassDate
Q1 · analysis[2 marks]

State what the resultant force on an object is equal to, and write the equation linking force, change in momentum and time.

Q2 · calc[2 marks]

The momentum of an object changes by 24 kg m/s in a time of 0.40 s. Calculate the average resultant force.

Q3 · calc[3 marks]

A 2.0 kg trolley speeds up from 3.0 m/s to 8.0 m/s in 2.0 s. Calculate the resultant force acting on it.

Q4 · analysis[3 marks]

Explain, using the idea of change of momentum, how the crumple zone of a car reduces the force on the passengers in a crash.

Q5 · calc[3 marks]

A 0.20 kg ball hits the floor moving downward at 5.0 m/s and bounces straight up at 3.0 m/s. The contact with the floor lasts 0.10 s. Taking upward as positive, calculate the average force the floor exerts on the ball.

Q6 · analysis[2 marks]

Two identical eggs are dropped from the same height. One lands on a hard tiled floor and breaks; the other lands on a soft cushion and survives. Explain the difference in terms of force and time.

Answer key and marking notes
Q1 · 2 marks
  • The resultant force equals the rate of change of momentum. ✓
  • F = Δp ÷ t (= (mv − mu) ÷ t). ✓
Q2 · 2 marks
  • F = Δp ÷ t = 24 ÷ 0.40

    F = 60 N

Q3 · 3 marks
  • Δp = m(v − u) = 2.0 × (8.0 − 3.0) = 10 kg m/s F = Δp ÷ t = 10 ÷ 2.0

    F = 5.0 N

Q4 · 3 marks
  • The change in momentum is fixed by the mass and speed of the car. ✓
  • The crumple zone folds, increasing the time over which the car stops. ✓
  • Since F = Δp ÷ t, a longer time gives a smaller force on the passengers. ✓
Q5 · 3 marks
  • Δp = m(v − u) = 0.20 × (3.0 − (−5.0)) Δp = 0.20 × 8.0 = 1.6 kg m/s F = 1.6 ÷ 0.10

    F = 16 N upward

    downward velocity is −5.0, so the change is 8.0, not 2.0

Q6 · 2 marks
  • Both eggs have the same change in momentum on landing. ✓
  • The cushion increases the stopping time, so F = Δp ÷ t gives a smaller force, low enough not to break the egg. ✓
Quiz

2 multiple-choice questions on this lesson

From the topic question bank. Assign them in the app for a marked score in your gradebook, or run the topic as a class game.

Q11 mark

A force of 50 N acts on a ball for 0.30 s. What is the impulse, which equals the change in momentum?

  • A0.0060 N s
  • B15 N s
  • C17 N s
  • D167 N s
Q21 mark

A car airbag increases the time taken to bring a passenger to rest in a crash. For the same change in momentum, what is the effect on the force on the passenger?

  • Athe force increases
  • Bthe force decreases
  • Cthe force is unchanged
  • Dthe force becomes zero
Quiz key
Q1: B

impulse = Ft = 50 × 0.30 = 15 N s, equal to a change in momentum of 15 kg m/s. Option A inverts the calculation; C adds the numbers; D divides.

Q2: B

With the same change in momentum spread over a longer time, F = Δp ÷ t is smaller, so the force on the passenger decreases. This is why airbags reduce injury. Option A reverses the relationship.

Lab and demo

What to project

The student lesson embeds these tabs. Open them full screen on the projector; every slider has a drag handle on the stage.

Slides

Slides for this lesson

A projectable deck for every pack is on the way. Until then, present the student lesson full screen: its sections, figure and lab tabs follow the same order as the plan above.

Also for this topic

Everything else you can use

Original work by the TheLucidSTEM team. The worksheet items are written in the style of the papers; no past paper question is reproduced.
Previous lessonMomentum and conservation