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Lesson pack · IGCSE Physics 0625 · 6.1.1 · Extended (Supplement)

Orbital speed

Once around, divided by time. A planet on a circular orbit travels the whole way round in one period.

Student lesson Lab, full screen
At a glance

The shape of the lesson

Topic
The Earth and the Solar System
Syllabus reference
Cambridge IGCSE Physics 0625, 6.1.1
Level
Extended (Supplement)
Duration
45 minutes, lab-led; stretches to a 60 minute block (see the contingency notes)
Position in topic
Lesson 2 of 5 in The Earth and the Solar System; follows The Earth, day, night and seasons; leads into The Solar System
Central model
An orbiting body moves at v = 2 pi r divided by T, the circumference of the orbit divided by the time for one orbit.
Cooperative structure
Assessment
Stage 1 check and the exam-style plenary from the student lesson, plus the worksheet as the exit task
Learning objectives

By the end of the lesson, learners can

Section by section
  • Speed around the loop: Change the orbital radius and period and watch the orbital speed that results.
  • Circumference over time: The distance for one orbit is the circumference 2 pi r, and dividing by the period gives the speed.
Key points to leave on the board
  • Formula: v = 2(pi)r / T.
  • Units: r in metres, T in seconds, v in m/s.
  • Rearrange: to find r or T when needed.
The core visual model

One picture every idea returns to

An orbiting body moves at v = 2 pi r divided by T, the circumference of the orbit divided by the time for one orbit. Planets closer to the Sun travel faster and take less time to go round.

Lesson sequence

Forty-five minutes, phase by phase

TimePhaseWhat happens in the roomGrouping
0 to 5 minHook: predictOpen with the question in the title, Once around, divided by time.. A planet on a circular orbit travels the whole way round in one period.Whole class, then pairs
5 to 17 minTeach and check: Speed around the loopChange the orbital radius and period and watch the orbital speed that results. Project tab 5 of the lab (Orbital speed) and let a student drive it while the class predicts.Whole class, then pairs
17 to 30 minTeach and check: Circumference over timeThe distance for one orbit is the circumference 2 pi r, and dividing by the period gives the speed. Model the worked example Worked example on the board, one line at a time.Round Table
30 to 36 minCheckThe four Stage 1 questions from the student lesson, answered on mini whiteboards or by show of fingers. Re-teach the one most get wrong.Individual, then whole class
36 to 43 minPlenaryThe exam-style questions from Stage 2, one at a time: thirty seconds alone, then a random call. The feedback lines in the key give the examiner's wording.Individual, random call
43 to 45 minExit and homeworkSet the worksheet below (6 questions, 15 marks). Learners self-assess against the objectives before they leave.Individual
Timing and contingency

Protect the parts that carry the learning

The sequence carries about fifty minutes of material, so the lab is driven by one student while the class predicts rather than explored freely. Times are a guide.

Protected: the check at 30 minutes. It is the only individual read on whether the key idea landed, and it is not cut.

Cut first if the build overruns: the last check in Circumference over time, never the check or the plenary.

In a 60 minute block: run worksheet questions 1 to 3 in class as a Rally Coach set and model both the hardest worked example and its check live.

Running the cooperative task

Round Table

One sheet travels round the team. Each student adds one line of working or one idea and passes it on, so the solution is built four hands at a time and every contribution is visible.

The full structure, with its variations and the other twelve, is on the cooperative-learning page.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
Use the full circumference 2 pi r, not just the radius, and keep r in metres and T in seconds.Planets further from the Sun move more slowly and take longer to orbit.
Worksheet

Orbital speed: worksheet

6 questions, 15 marks. Written in the style of the papers; no past paper question is reproduced.

NameClassDate
Q1 · analysis[2 marks]

Write down the equation for orbital speed, and state what each symbol means.

Q2 · calc[3 marks]

A planet orbits a star in a circle of radius 6.0 x 10 to the 10 m, with a period of 2.0 x 10 to the 7 s. Calculate its orbital speed.

Q3 · calc[3 marks]

A satellite moves at 7500 m/s in a circular orbit of radius 7.0 x 10 to the 6 m. Calculate its period.

Q4 · analysis[2 marks]

Two satellites have the same period, but one orbits at twice the radius of the other. Compare their orbital speeds.

Q5 · analysis[2 marks]

Explain why a satellite with a longer period, at the same orbital radius, moves more slowly.

Q6 · calc[3 marks]

The Moon orbits the Earth at a radius of about 3.8 x 10 to the 8 m with a period of about 2.4 x 10 to the 6 s. Estimate its orbital speed.

Answer key and marking notes
Q1 · 2 marks
  • v = 2(pi)r / T. ✓
  • r is the orbit radius, T is the period (time for one orbit), v is the orbital speed. ✓
Q2 · 3 marks
  • v = 2(pi)r / T = 2 x (pi) x (6.0 x 10 to the 10) / (2.0 x 10 to the 7)

    v = 1.9 x 10 to the 4 m/s (about 19000 m/s)

Q3 · 3 marks
  • T = 2(pi)r / v = 2 x (pi) x (7.0 x 10 to the 6) / 7500

    T = 5900 s (to 2 significant figures)

Q4 · 2 marks
  • Speed is proportional to radius when the period is the same. ✓
  • The one at twice the radius moves at twice the speed. ✓
Q5 · 2 marks
  • It travels the same distance (2(pi)r) round the orbit. ✓
  • But it takes a longer time, so its speed (distance / time) is smaller. ✓
Q6 · 3 marks
  • v = 2(pi)r / T = 2 x (pi) x (3.8 x 10 to the 8) / (2.4 x 10 to the 6)

    v = 1000 m/s (about 1.0 x 10 to the 3 m/s)

Quiz

3 multiple-choice questions on this lesson

From the topic question bank. Assign them in the app for a marked score in your gradebook, or run the topic as a class game.

Q11 mark

A planet moves in a near-circular orbit of radius 4.5 × 1012 m with an orbital period of 9.0 × 109 s. What is its orbital speed? (v = 2πr ÷ T)

r v
  • Aabout 3.1 × 103 m/s
  • Babout 5.0 × 102 m/s
  • Cabout 1.6 × 103 m/s
  • Dabout 2.0 × 103 m/s
Q21 mark

A satellite orbits at a speed of 1.0 × 104 m/s in a circular orbit of radius 6.0 × 1011 m. What is its orbital period? (rearrange v = 2πr ÷ T)

  • Aabout 3.8 × 108 s
  • Babout 6.0 × 107 s
  • Cabout 1.9 × 108 s
  • Dabout 1.7 × 108 s
Q31 mark

Compared with the inner planets, the outer planets of the Solar System have:

  • Alarger orbits, longer periods, and slower orbital speeds
  • Bsmaller orbits and faster speeds
  • Cthe same orbital speed as the inner planets
  • Dlonger periods but faster speeds
Quiz key
Q1: A

v = 2πr ÷ T = 2π × (4.5 × 10¹²) ÷ (9.0 × 10⁹) = 2π × 500 ≈ 3.1 × 10³ m/s. Option B forgets the factor of 2π and C uses π instead of 2π.

Q2: A

T = 2πr ÷ v = 2π × (6.0 × 10¹¹) ÷ (1.0 × 10⁴) = 2π × 6.0 × 10⁷ ≈ 3.8 × 10⁸ s. Option B drops the 2π and C uses π instead of 2π.

Q3: A

Outer planets have larger orbital radii, so they travel further and take much longer to complete an orbit, and they move more slowly. Neptune, for example, takes about 165 Earth years for one orbit.

Lab and demo

What to project

The student lesson embeds these tabs. Open them full screen on the projector; every slider has a drag handle on the stage.

Slides

Slides for this lesson

A projectable deck for every pack is on the way. Until then, present the student lesson full screen: its sections, figure and lab tabs follow the same order as the plan above.

Also for this topic

Everything else you can use

Original work by the TheLucidSTEM team. The worksheet items are written in the style of the papers; no past paper question is reproduced.
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