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Lesson plan · AS 9702 · 2.1 · Kinematics

Projectile motion, two motions at once

A projectile is a constant horizontal velocity combined with vertical free fall, the two independent and sharing only the time t. Resolve the launch velocity, solve each motion separately, and find the time of flight, range, height and the velocity at any instant.

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At a glance

The shape of the lesson

Topic
Projectile motion (subtopic 2.1)
Syllabus reference
Cambridge International AS & A Level Physics 9702, 2.1 (Topic 2: Kinematics)
Level
AS (first year)
Duration
60 minutes (single period)
Prior knowledge
Vectors and components (1.4), the equations of motion and free fall (2.1)
Central visual model
A parabolic path: equal horizontal steps, growing vertical drops
Simulation
Projectile Motion, the two motions solved together
Cooperative structure
Cooperative Concept Mapping (cards + teacher model map in the activity materials)
21st century skills
Critical Thinking, Creativity, Collaboration
Assessment
An exit ticket, plus each group's concept map and the links each learner justified
Learning objectives

By the end of the lesson, learners can

AS (all learners)
  • describe projectile motion as a constant horizontal velocity combined with vertical free fall, the two being independent
  • resolve a launch velocity into horizontal and vertical components
  • apply constant velocity to the horizontal motion and the equations of motion to the vertical motion
  • find the time of flight, the range, the maximum height and the velocity at a given instant
  • describe qualitatively the effect of air resistance on the trajectory

Key vocabulary

projectile, horizontal and vertical components, independence of motions, time of flight, range, maximum height, resultant velocity, air resistance. Each term is introduced as it is first needed.

The core ideas

Two independent motions, one shared time

With no air resistance the only force on a projectile is its weight, so the horizontal acceleration is zero and the vertical acceleration is g downward. The horizontal and vertical motions are independent and share only the time t: a ball launched horizontally and a ball simply dropped from the same height land together.

A horizontally launched projectile shown at equal time intervals, with equal horizontal steps and growing vertical drops.
Equal horizontal steps, growing vertical drops
A launch velocity resolved into a constant horizontal component u cos theta and a vertical component u sin theta.
Resolve u into u cos θ and u sin θ first

For a launch speed u at angle θ, the horizontal component u cos θ stays constant and the vertical component u sin θ changes under gravity. Solve the horizontal motion with x = (u cos θ) t and the vertical motion with the suvat equations using a = g. The vertical motion sets the time of flight and the maximum height; the range is the horizontal velocity multiplied by the time of flight.

Velocity at an instant, and air resistance

The velocity at any point is the vector sum of the constant horizontal component and the changing vertical component, so at the top of the path the velocity is not zero: the horizontal component is still present. With air resistance the range and the maximum height are reduced and the path becomes asymmetric, with a steeper descent.

The constant horizontal and changing vertical components of velocity combining to a resultant at a point on the path.
v is the vector sum of vₓ and vₙ
Projectile trajectories with and without air resistance, the air-resistance path shorter, lower and asymmetric.
Air resistance: shorter, lower, asymmetric
Lesson sequence

Sixty minutes, phase by phase

TimePhaseWhat happens in the roomResources
0 to 5 minStarterShow a dropped ball and a horizontally launched ball landing together; ask why, and draw out the independence of the vertical motion.Slide 1, fig-projectile-path
5 to 17 minTeach: resolveResolve the launch velocity; set up the horizontal and vertical motions separately.Slides 2 to 5, fig-components
17 to 30 minModelWork a horizontal launch and an angled launch, finding time, range and height; find a velocity at an instant.Slides 6 to 10, fig-velocity-at-point
30 to 50 minActivityRun Cooperative Concept Mapping; groups arrange and link the concept cards, justifying each link.Concept card set, large paper
50 to 60 minPlenaryCompare maps; add air resistance as a final node; exit ticket.Slide 11, fig-air-resistance-traj
Worked examples for the board

A horizontal launch and an angled launch

Example 1: a horizontal launch

A ball is thrown horizontally at 15 m s−1 from a cliff 20 m high. Take g = 9.81 m s−2. Find the time to land, the horizontal distance, and the vertical speed on landing.

Time (vertical): 20 = ½ × 9.81 × t², so t² = 4.08 and t = 2.0 s
Horizontal distance: x = 15 × 2.0 = 30 m
Vertical speed: vy = g t = 9.81 × 2.0 = 20 m s−1

Example 2: an angled launch

A projectile is launched at 25 m s−1 at 30 degrees above the horizontal over level ground. Find the components, the time of flight, the range and the maximum height.

Components: u cos 30° = 21.7 m s−1 (horizontal); u sin 30° = 12.5 m s−1 (vertical)
Time of flight: time to the top = 12.5 / 9.81 = 1.27 s, so total T = 2.55 s
Range: x = 21.7 × 2.55 = 55 m
Maximum height: H = (12.5)² / (2 × 9.81) = 8.0 m
Running the cooperative task

Cooperative Concept Mapping

Projectile motion is where vectors, the equations of motion and free fall all come together, so it is an ideal point to map how the ideas connect. Each group is given a set of concept cards and a large sheet; they arrange the cards and join them with labelled arrows that state the relationship (for example splits into, is, determines, gives). Every learner must justify aloud at least one link they drew. Groups then compare maps and add air resistance as a final node. A full step-by-step facilitation guide, with the concept card set and a teacher model map, is provided as the activity in this bundle, so it can be run faithfully.

A skeleton concept map of projectile motion linking horizontal and vertical motion to the time of flight, range and height.
A skeleton: arrange the cards and label every link

Why it suits this lesson. Mapping forces learners to make the connections between motions explicit, which is exactly where projectile understanding tends to break. Every link is owned and justified by a named learner, which gives individual accountability, and gaps in a map reveal where understanding is missing.

Examiner traps to pre-empt

What to head off, and how

Trap learners fall intoTeaching move that pre-empts it
Thinking the horizontal motion slows down.With no air resistance the horizontal velocity stays constant; nothing acts horizontally.
Believing a horizontally launched ball and a dropped ball take different times to fall.They share the same vertical motion and land together; the horizontal motion is independent.
Treating the launch speed as if it acts horizontally.The speed must be resolved into components first; only u cos θ is horizontal.
Saying the velocity at the top of the path is zero.The vertical component is zero there, but the horizontal component is still present.
Differentiation and assessment

Support, challenge and the checks

Assessment is formative. Exit ticket question 1: a stone is thrown horizontally at 8.0 m s−1 from a height of 5.0 m, find the time to land and the horizontal distance. Exit ticket question 2: explain why the horizontal velocity of a projectile does not change when air resistance is ignored. Each group's map and the links learners justified make the connections visible.

Equipment and resources

Original work by the TheLucidSTEM team. Items are written in the style of the papers; no past paper question is reproduced. Supplied in editable formats so you can adapt them freely.
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